我需要查找在 Adam Rivera 拥有帐户的所有分支机构中拥有帐户的客户 ID、姓氏和出生日期。
这是银行架构:
§ Customer = {customerID, firstName, lastName, income, birthDate }
§ Account = {accNumber, type, balance, branchNumberFK-Branch}
§ Owns = {customerIDFK-Customer, accNumberFK-Account}
§ Transactions = {transNumber, accNumberFK-Account, amount}
§ Employee = {sin, firstName, lastName, salary, branchNumberFK-Branch}
§ Branch = {branchNumber, branchName, managerSINFK-Employee, budget}
亚当·里维拉拥有的所有分支编号,查询给出:
branchNumber
1
4
SELECT b2.branchNumber -- all branches that Adam Rivera owns
FROM Customer c2 join Owns o2 on c2.customerID = o2.customerID join Account a2 on a2.accNumber = o2.accNumber join Branch b2 on b2.branchNumber = a2.branchNumber
WHERE c2.firstName = 'Adam' and c2.lastName = 'Rivera'
客户在亚当·里维拉的分行拥有帐户的分行号码列表,重用是:
cusID lstName birthDate branch#
10839 Hayes 1977-06-09 1
10839 Hayes 1977-06-09 4
11790 Green 1920-11-19 1
11790 Green 1920-11-19 1
13230 Brooks 1967-05-04 1
13423 Simmons 1955-03-21 1
13423 Simmons 1955-03-21 4
13697 Hill 1951-03-07 1
13697 Hill 1951-03-07 4
14295 Ramirez 1983-06-30 4
18166 Barnes 1951-03-07 1
19973 Kelly 1987-07-15 1
22050 Sanchez 1935-01-08 1
.......
SELECT c1.customerID, c1.lastName, c1.birthDate, b1.branchNumber
FROM Customer c1 join Owns o1 on c1.customerID = o1.customerID join Account a1 on a1.accNumber = o1.accNumber join Branch b1 on b1.branchNumber = a1.branchNumber
WHERE EXISTS
SELECT b3.branchNumber
FROM Customer c3 join Owns o3 on c3.customerID = o3.customerID join Account a3 on a3.accNumber = o3.accNumber join Branch b3 on b3.branchNumber = a3.branchNumber
WHERE c3.firstName = 'Adam' and c3.lastName = 'Rivera' and b1.branchNumber = b3.branchNumber
以下结果应返回客户没有帐户的所有分支机构,如果客户在每个分支机构都有一个帐户,则此结果为空。
WHERE NOT EXISTS
(branch numbers that Adam Rivera owns)
EXCEPT
(a list of branch numbers that a customer has account at Adam Rivera's branches)
在 WHERE 之后使用不存在,应该返回拥有所有 Adam Rivera 帐户的客户
这是我写的查询。
SELECT c1.customerID, c1.lastName, c1.birthDate
FROM Customer c1 join Owns o1 on c1.customerID = o1.customerID join Account
a1 on a1.accNumber = o1.accNumber join Branch b1 on b1.branchNumber =
a1.branchNumber
WHERE NOT EXISTS
(-- all branch numbers that Adam Rivera owns
(SELECT b2.branchNumber
FROM Customer c2 join Owns o2 on c2.customerID = o2.customerID join
Account a2 on a2.accNumber = o2.accNumber join Branch b2 on b2.branchNumber = a2.branchNumber
WHERE c2.firstName = 'Adam' and c2.lastName = 'Rivera')
EXCEPT
-- a list of branch numbers that a customer has account at Adam Rivera's branches
(SELECT b3.branchNumber
FROM (Customer c3 join Owns o3 on c3.customerID = o3.customerID join Account a3 on a3.accNumber = o3.accNumber join Branch b3 on b3.branchNumber = a3.branchNumber)
WHERE c3.firstName = 'Adam' and c3.lastName = 'Rivera' and b1.branchNumber = b3.branchNumber )
)
查询应返回 Hayes、Simmons、Hill。但结果不返回任何内容(错误)。我无法弄清楚这里出了什么问题。
这里有一种方法:
with ar as (
select distinct a.branchNumber
from Customer c join
Owns o
on c.customerID = o.customerID join
Account a
on a.accNumber = o.accNumber
where c.firstName = 'Adam' and c.lastName = 'Rivera'
)
select o.customerId
from Owns o
Account a
on a.accNumber = o.accNumber join
ar
on ar.branchNumber = a.branchNumber
group by o.customerId
having count(distinct a.branchNumber) = (select count(*) from ar);
子查询是里维拉先生拥有的帐户。 join
与每个帐户匹配。 group by
和having
计算每个客户的不同分行的数量,并检查该号码是否与里维拉先生的号码相匹配。