需要为一个销售订单打印五个序列号，而不是ir.sequence

Question

我写了一个代码来打印一个销售订单的五个序列号但它影响了最后一个销售订单号，它跳过了5个订单号

我必须为1个没有ir序列的销售订单打印5个序列号

ticket = fields.Char(string="Ticket", readonly=True, required=True, copy=False, default='New')
@api.multi
def action_confirm(self): 
result = super(SaleOrder, self).action_confirm()
len_count = []
ticket_list = []
tickets = ""
count = 5
for i in range(count):
x = self.env['ir.sequence'].next_by_code('sale.order')
if not len(len_count) == 5:
if not tickets:
tickets = x 
else:
tickets = tickets + ',' + x
print tickets
print 'abc'

ticket_list.append(str(tickets))
self.ticket = ticket_list
print ticket_list
ctx = dict(self.env.context or {})
ctx.update({
'sale_action_new': ticket_list,
})    
print ctx
template = self.env.ref('sale_order.email_template_ticket')
template.with_context(ctx).send_mail(self.id)

Answer 1

让我来帮忙。

start = self.id               //sales-order id
limit = start + 5 
for x in range(start, limit):
if not tickets:
tickets = x 
else:
tickets = tickets + ',' + x