在 MS Server 2014 中将字符串的每个字符替换为另一个字符



我正在使用Microsoft SQL Server 2014,我正在尝试更新表中的某些列。

我想用另一个字符替换字符串的每个字符。

例如,单词:

HELLO123

我想用 T、E 和 Q、L 和 Y、O 和 I、1 和 6、2 和 7 和 3 用 8

代替等等。我不确定Microsoft SQL Server 2014是否支持正则表达式,即创建一个函数并循环遍历每个字符并替换将在具有数百万行的表上花费很长时间。

有没有人有任何解决方案可以像正则表达式一样工作并且可以快速?

谢谢

如果你没有注意到,REPLACE的问题在于你需要嵌套这些值,但是,因为你嵌套的东西REPLACE(REPLACE('HELLO','H','E'),'E','Q')会返回'QQLLO'而不是'EQLLO'。如评论中所述,SQL Server 2017引入了TRANSLATE,它只会处理一次字符,但是,当您使用2014时,您可以';t 使用它 (TRANSLATE('HELLO','HE','EQ')(。

您可以做的是创建一个查找表,然后将数据拆分为字符并重建它。对于大量数据,这不会很快,不,它不会变得更快;但它会"完成工作":

--Create a table for the Cipher characters
CREATE TABLE dbo.CharCipher (InputChar char(1) NOT NULL,
OutputChar char(1) NOT NULL);
GO
--Add a Clustered Primary Key
ALTER TABLE dbo.CharCipher ADD CONSTRAINT PK_CharCipher PRIMARY KEY CLUSTERED (InputChar);
GO
--Ensure that the Output character us unique too    
CREATE UNIQUE NONCLUSTERED INDEX UX_CipherOutput ON dbo.CharCipher (OutputChar);
GO
--Add your Ciphers
INSERT INTO  dbo.CharCipher (InputChar,
OutputChar)
VALUES ('H','T'),
('E','Q'),
('L','Y'),
('O','I'),
('1','6'),
('2','7'),
('3','8');
GO
--Create a Sample table
CREATE TABLE dbo.YourTable (YourString varchar(15));
INSERT INTO dbo.YourTable (YourString)
VALUES('HELLO123');
GO
--And now the "Mess"... I mean solution
WITH N AS(
SELECT N
FROM (VALUES(NULL),(NULL),(NULL),(NULL),(NULL),(NULL),(NULL),(NULL),(NULL),(NULL))N(N)),
Tally AS(
SELECT TOP (8000) ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) AS I
FROM N N1, N N2, N N3, N N4)
SELECT YT.YourString,
(SELECT ISNULL(CC.OutputChar,V.YourChar)
FROM Tally T
CROSS APPLY (VALUES(CONVERT(char(1),SUBSTRING(YT.YourString,T.I,1))))V(YourChar)
LEFT JOIN dbo.CharCipher CC ON V.YourChar = CC.InputChar
WHERE T.I <= LEN(YT.YourString)
ORDER BY T.I
FOR XML PATH(''),TYPE).value('.','varchar(8000)') AS NewString
FROM dbo.YourTable YT;
GO
--Clean up
DROP TABLE dbo.YourTable;
DROP TABLE dbo.CharCipher;
--this could work if the strings are all uppercase --<-- not true
--you could use nchar & foreign characters and handle everything correctly...it is just a pain to type...
declare @s varchar(20) = 'HELLO123';
--lower case everything
select @s = lower(@s)
--handle numbers with non printable characters  --> number to char() --> char() to new number
select @s = replace(replace(replace(replace(replace(replace(@s, '1', char(1)), '2', char(2)), '3', char(3)), char(1), '6'), char(2), '7'), char(3), '8')

--handle letters with case sensitive replacement (using a CS collation)
--(all letters are lowercased)lowercase letter --> new uppercase letter
select replace(replace(replace(replace(@s collate SQL_Latin1_General_CP1_CS_AS, 'h' , 'T'), 'e', 'Q'), 'l', 'Y'),  'o', 'I'); 

SELECT UPPER(REPLACE(REPLACE(LOWER('HELLO') collate SQL_Latin1_General_CP1_CS_AS, 'h','E'),'e','Q'));

GO
/*
SELECT dbo.shiftchars('0123456789::ABCDEFGHIJKLMNOPQRSTUVWXYZ::abcdefghijklmnopqrstuvwxyz');
just for fun *using a single replace()*
not for millions of rows
suitable for standard latin alphanumeric
extended ascii & non printable chars are not handled correctly.
*/
CREATE FUNCTION dbo.shiftchars(@s VARCHAR(8000))
RETURNS VARCHAR(8000)
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS
BEGIN
SELECT @s = REPLACE(@s, f collate SQL_Latin1_General_CP1_CS_AS , t)
FROM
(
VALUES
(1, '1', CHAR(1)),
(1, '2', CHAR(2)),
(1, '3', CHAR(3)),
(1, '4', CHAR(4)),
(1, '5', CHAR(5)),
(1, '6', CHAR(6)),
(1, '7', CHAR(7)),
(1, '8', CHAR(8)),
(1, '9', CHAR(9)),
(1, '0', CHAR(254)),
(1, 'A', CHAR(128)),
(1, 'B', CHAR(129)),
(1, 'C', CHAR(130)),
(1, 'D', CHAR(131)),
(1, 'E', CHAR(132)),
(1, 'F', CHAR(133)),
(1, 'G', CHAR(134)),
(1, 'H', CHAR(135)),
(1, 'I', CHAR(136)),
(1, 'J', CHAR(137)),
(1, 'K', CHAR(138)),
(1, 'L', CHAR(139)),        
(1, 'M', CHAR(140)),
(1, 'N', CHAR(141)),
(1, 'O', CHAR(142)),        
(1, 'P', CHAR(143)),
(1, 'Q', CHAR(144)),
(1, 'R', CHAR(145)),        
(1, 'S', CHAR(146)),
(1, 'T', CHAR(147)),    
(1, 'U', CHAR(148)),        
(1, 'V', CHAR(149)),
(1, 'W', CHAR(150)),
(1, 'X', CHAR(151)),        
(1, 'Y', CHAR(152)),
(1, 'Z', CHAR(153)),
(1, 'a', CHAR(154)),
(1, 'b', CHAR(155)),
(1, 'c', CHAR(156)),
(1, 'd', CHAR(157)),
(1, 'e', CHAR(158)),
(1, 'f', CHAR(159)),
(1, 'g', CHAR(160)),
(1, 'h', CHAR(161)),
(1, 'i', CHAR(162)),
(1, 'j', CHAR(163)),
(1, 'k', CHAR(164)),
(1, 'l', CHAR(165)),        
(1, 'm', CHAR(166)),
(1, 'n', CHAR(167)),
(1, 'o', CHAR(168)),        
(1, 'p', CHAR(169)),
(1, 'q', CHAR(170)),
(1, 'r', CHAR(171)),        
(1, 's', CHAR(172)),
(1, 't', CHAR(173)),    
(1, 'u', CHAR(174)),        
(1, 'v', CHAR(175)),
(1, 'w', CHAR(176)),
(1, 'x', CHAR(177)),        
(1, 'y', CHAR(178)),
(1, 'z', CHAR(179)),
--------------------
(2, CHAR(1), '6'),
(2, CHAR(2), '7'),
(2, CHAR(3), '8'),
(2, CHAR(4), '9'),
(2, CHAR(5), '0'),
(2, CHAR(6), '1'),
(2, CHAR(7), '2'),
(2, CHAR(8), '3'),
(2, CHAR(9), '4'),
(2, CHAR(254), '5'),
(2, CHAR(128), 'M'),
(2, CHAR(129), 'N'),
(2, CHAR(130), 'O'),
(2, CHAR(131), 'P'),
(2, CHAR(132), 'Q'),
(2, CHAR(133), 'R'),
(2, CHAR(134), 'S'),
(2, CHAR(135), 'T'),
(2, CHAR(136), 'U'),
(2, CHAR(137), 'V'),
(2, CHAR(138), 'W'),
(2, CHAR(139), 'X'),            
(2, CHAR(140), 'Y'),
(2, CHAR(141), 'Z'),
(2, CHAR(142), 'A'),            
(2, CHAR(143), 'B'),
(2, CHAR(144), 'C'),
(2, CHAR(145), 'D'),            
(2, CHAR(146), 'E'),
(2, CHAR(147), 'F'),        
(2, CHAR(148), 'G'),            
(2, CHAR(149), 'H'),
(2, CHAR(150), 'I'),
(2, CHAR(151), 'J'),            
(2, CHAR(152), 'K'),
(2, CHAR(153), 'L'),
(2, CHAR(154), 'm'),
(2, CHAR(155), 'n'),
(2, CHAR(156), 'o'),
(2, CHAR(157), 'p'),
(2, CHAR(158), 'q'),
(2, CHAR(159), 'r'),
(2, CHAR(160), 's'),
(2, CHAR(161), 't'),
(2, CHAR(162), 'u'),
(2, CHAR(163), 'v'),
(2, CHAR(164), 'w'),
(2, CHAR(165), 'x'),            
(2, CHAR(166), 'y'),
(2, CHAR(167), 'z'),
(2, CHAR(168), 'a'),            
(2, CHAR(169), 'b'),
(2, CHAR(170), 'c'),
(2, CHAR(171), 'd'),            
(2, CHAR(172), 'e'),
(2, CHAR(173), 'f'),        
(2, CHAR(174), 'g'),            
(2, CHAR(175), 'h'),
(2, CHAR(176), 'i'),
(2, CHAR(177), 'j'),            
(2, CHAR(178), 'k'),
(2, CHAR(179), 'l')                 
) AS v(o, f, t)
ORDER BY o;
RETURN (@s);
END

在 Sql Server 2014 上可以进行这样的加扰。
即使没有 UDF 或 CLR。

这是一种使用FOR XML上的OUTER APPLY来展开和替换[0-9A-Za-z]范围的字符的方法。

示例数据:

create table test 
(
id int identity(1,1) primary key,
col nvarchar(42)
);
insert into test (col) values
(N'HELLO 0123'),
(N'01234π56789'),
(N'abcdefghijklm>nopqrstuvwxyz'),
(N'ABCDEFGHIJKLM✓NOPQRSTUVWXYZ');

数:

--
-- Temporary tally table with numbers
-- Will be used to unfold that characters
--
if object_id('tempdb..#nums') is not null
drop table #nums;
create table #nums (n int primary key);
with rcte as
(
select 1 n, max(len(col)) max_n
from test
union all 
select n+1, max_n
from rcte 
where n <= max_n
)
insert #nums (n)
select n 
from rcte
option (maxrecursion 4000);

查询:

select t.*, a.scramble
from test t
outer apply
(
select q.x.value('.','NVARCHAR(MAX)') as scramble
from
(
select
case 
when substring(col,n,1) between N'0' and N'9'
then substring(
N'5678901234',charindex(substring(col,n,1),
N'0123456789'),1)
when unicode(substring(col,n,1)) between unicode(N'a') and unicode(N'z')
then substring(
N'nomrqputswvyzxiacbedghfjlk',charindex(substring(col,n,1),
N'abcdefghijklmnopqrstuvwxyz'),1)
when unicode(substring(col,n,1)) between unicode(N'A') and unicode(N'Z')
then substring(
N'NOMRQPUTSWVYZXIACBEDGHFJLK',charindex(substring(col,n,1),
N'ABCDEFGHIJKLMNOPQRSTUVWXYZ'),1)
else substring(col,n,1)
end [text()]
from #nums
where n between 1 and len(col)
order by n
for xml path (''), type
) q(x)
where q.x is not null
) a;

结果:

ID | col | scramble                     -: |:---------------------------- |:----------------------------  1 |你好 0123 |秦羲 5678                    2 |01234π56789                  |56789π01234                  3 |abcdefghijklm>nopqrstuvwxyz |nomrqputswvyz>xiacbedghfjlk   4 |ABCDEFGHIJKLM✓NOPQRSTUVWXYZ |NOMRQPUTSWVYZ✓XIACBEDGHFJLK

A test ondb<>fiddle here

--

针对VARCHAR更具体的解决方案:

select t.*, a.scramble
from test t
outer apply
(
select q.x.value('.', 'VARCHAR(MAX)') as scramble
from
(
select
case 
when substring(col,n,1) between '0' and '9'
then substring(
'5678901234',charindex(substring(col,n,1),
'0123456789'),1)
when ascii(substring(col,n,1)) between ascii('a') and ascii('z')
then substring(
'nomrqputswvyzxiacbedghfjlk',charindex(substring(col,n,1),
'abcdefghijklmnopqrstuvwxyz'),1)
when ascii(substring(col,n,1)) between ascii('A') and ascii('Z')
then substring(
'NOMRQPUTSWVYZXIACBEDGHFJLK',charindex(substring(col,n,1),
'ABCDEFGHIJKLMNOPQRSTUVWXYZ'),1)
else substring(col,n,1)
end
from #nums
where n between 1 and len(col)
order by n
for xml path (''), type
) q(x)
where q.x is not null
) a;

或者,执行旋转加扰的解决方案:

select t.*, a.scramble
from test t
outer apply
(
select q.x.value('.', 'VARCHAR(MAX)') as scramble
from
(
select 
case
when substring(col,n,1) between '0' and '9'
then char(ascii('0')+(ascii(substring(col,n,1))-ascii('0')+5)%10)
when ascii(substring(col,n,1)) between ascii('a') and ascii('z')
then char(ascii('a')+(ascii(substring(col,n,1))-ascii('a')+13)%26)
when ascii(substring(col,n,1)) between ascii('A') and ascii('Z')
then char(ascii('A')+(ascii(substring(col,n,1))-ascii('A')+13)%26)
else substring(col,n,1)
end
from #nums
where n between 1 and len(col)
order by n
for xml path (''), type
) q(x)
) a

在这里测试数据库<>小提琴

请注意,对于 Sql Server 2017+ 解决方案,STRING_SPLIT可以替换FOR XML。 但话又说回来,人们可以简单地使用TRANSLATE

例:

UPDATE test
SET col = TRANSLATE(col, 
'0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ' collate Latin1_General_CS_AS, 
'5678901234nomrqputswvyzxiacbedghfjlkNOMRQPUTSWVYZXIACBEDGHFJLK');

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