在下面的课程中,我试图打印工资系统中员工的详细信息。注意,波特、药剂师和外科医生都继承自雇员。
但是,它只是重复打印添加到数组中的第一个雇员的详细信息。我知道预期的输出,但我无法复制它。
类:public class PayrollManager {
public static final int HOURS_PER_WEEK = 35;
public static Employee[] employees = new Employee[6];
public static void main(String[] args) {
// create all employees
Employee generalEmployee = new Employee("Odd", "Jobbie", 10.50);
Employee porter1 = new Porter("Ivana", "Patient", 10.50, "Royal");
Employee porter2 = new Porter("Amanda", "Pushabed", 10.50, "BCH");
Employee surgeon1 = new Surgeon("Jack", "Ripper", 55.25, "Renal",
650.00);
Employee surgeon2 = new Surgeon("Edward", "Lister", 55.25, "Vascular",
800.00);
Employee pharmacist = new Pharmacist("Poppy", "Pill", 30.50, 7, 750);
// call method to handle adding the employees to the list
addEmployeeToList(generalEmployee);
addEmployeeToList(porter1);
addEmployeeToList(porter2);
addEmployeeToList(surgeon1);
addEmployeeToList(surgeon2);
addEmployeeToList(pharmacist);
// show all employees
displayAllEmployees();
System.out.println();
// run payroll
processWeeklyPayroll();
}// end of main
/**
* Method to add an Employee to an array
*
* @param e
*/
public static void addEmployeeToList(Employee e) {
for (int loop = 0; loop < employees.length; loop++) {
// check there is a space
if (employees[loop] == null) {
// add it to free space
employees[loop] = e;
}
}
}
public static void displayAllEmployees() {
for (Employee e : employees) {
if (e != null) {
e.displayAll();
System.out.println();
}
}
}
public static void processWeeklyPayroll() {
for (Employee e : employees) {
if (e != null) {
e.calculateWeeklySalary(HOURS_PER_WEEK);
// line break
System.out.println();
}
}
}
}
当前输出:[Employee] Odd Jobbie 10.500000
[Employee] Odd Jobbie 10.500000
[Employee] Odd Jobbie 10.500000
[Employee] Odd Jobbie 10.500000
[Employee] Odd Jobbie 10.500000
[Employee] Odd Jobbie 10.500000
Odd Jobbie [Base Rate Employee] : 35.000000hrs * £10.500000= £367.500000
Odd Jobbie [Base Rate Employee] : 35.000000hrs * £10.500000= £367.500000
Odd Jobbie [Base Rate Employee] : 35.000000hrs * £10.500000= £367.500000
Odd Jobbie [Base Rate Employee] : 35.000000hrs * £10.500000= £367.500000
Odd Jobbie [Base Rate Employee] : 35.000000hrs * £10.500000= £367.500000
Odd Jobbie [Base Rate Employee] : 35.000000hrs * £10.500000= £367.500000
注意,预期的输出应该是打印每个测试数据成员的详细信息,即每个药剂师,外科医生等…
这就是罪魁祸首:
public static void addEmployeeToList(Employee e) {
for (int loop = 0; loop < employees.length; loop++) {
// check there is a space
if (employees[loop] == null) {
// add it to free space
employees[loop] = e;
}
}
}
它只是将列表中的所有雇员设置为函数第一次调用时使用的参数;当你第一次调用它时,employees充满了null元素,所以条件总是为真;但第二次、第三次等调用时,所有元素都被设置为generalEmployee。
一个快速的修复方法是:
public static void addEmployeeToList(Employee e) {
for (int loop = 0; loop < employees.length; loop++) {
// check there is a space
if (employees[loop] == null) {
// add it to free space
employees[loop] = e;
break;
}
}
}
但是我强烈建议使用ArrayList。
ArrayList<Employee> employees = new ArrayList<Employee>(); //here you declare a dinamically resizing list.
employees.add(e) //this is how you add a new Employee to the list.