这里是xml
<?xml version="1.0" encoding="utf-8"?>
<Modules xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation="XSDQu3.xsd">
<Module code="CSE1246">
<Name shortName="ADSA">Applied Data Structures and Algorithms</Name>
<Level>1</Level>
<ResourcePerson>
<Name>Anwar</Name>
<Surname>Chutoo</Surname>
</ResourcePerson>
</Module>
<Module code="CSE2041">
<Name shortName="Web 2">Web Technologies II</Name>
<Level>2</Level>
<ResourcePerson>
<FullName>Shehzad Jaunbuccus</FullName>
</ResourcePerson>
</Module>
</Modules>
我有一个错误的名称。资源人员可以包含全名或姓名和姓氏。请帮助。这部分我做对了吗
xsd
<?xml version="1.0" encoding="utf-8"?>
<xs:schema elementFormDefault="qualified" xmlns:xs="http://www.w3.org/2001/XMLSchema">
<xs:complexType name="NameNSurnameType">
<xs:sequence>
<xs:element name="Name" type="xs:string"/>
<xs:element name="Surname" type="xs:string"/>
</xs:sequence>
</xs:complexType>
<xs:complexType name="ResourcePersonType">
<xs:sequence>
<xs:choice>
<xs:element name="NameNSurnameType" type="NameNSurnameType"/>
<xs:element name="FullName" type="xs:string"/>
</xs:choice>
</xs:sequence>
</xs:complexType>
<xs:attribute name="code">
<xs:simpleType>
<xs:restriction base="xs:ID">
<xs:pattern value="CSE(d{4})"/>
</xs:restriction>
</xs:simpleType>
</xs:attribute>
<xs:complexType name="nameType">
<xs:simpleContent>
<xs:extension base="xs:string">
<xs:attribute name="shortName" type="xs:string"/>
</xs:extension>
</xs:simpleContent>
</xs:complexType>
<xs:element name="Modules">
<xs:complexType>
<xs:sequence>
<xs:element name="Module" minOccurs="1" maxOccurs="unbounded">
<xs:complexType>
<xs:sequence>
<xs:element name="Name" type="nameType"/>
<xs:element name="Level" type="xs:positiveInteger"/>
<xs:element name="ResourcePerson" type="ResourcePersonType"/>
</xs:sequence>
<xs:attribute ref="code" use="required"/>
</xs:complexType>
</xs:element>
</xs:sequence>
</xs:complexType>
</xs:element>
</xs:schema>
我明白你的困惑;选择"选项"几乎可以是任何粒子;合成器(例如xs:sequence
或另一个xs:choice
)将匹配描述。您最少需要做的是更改以下定义。
<xs:complexType name="ResourcePersonType">
<xs:sequence>
<xs:choice>
<xs:sequence>
<xs:element name="Name" type="xs:string"/>
<xs:element name="Surname" type="xs:string"/>
</xs:sequence>
<xs:element name="FullName" type="xs:string"/>
</xs:choice>
</xs:sequence>
</xs:complexType>
如果你想引用这个名字,就像你想用全局复杂类型那样,那么你可以创建一个组并引用它。下面是与上述场景一致的修改后的XSD:
<?xml version="1.0" encoding="utf-8" ?>
<!-- XML Schema generated by QTAssistant/XSD Module (http://www.paschidev.com) -->
<xs:schema elementFormDefault="qualified" xmlns:xs="http://www.w3.org/2001/XMLSchema">
<xs:group name="NameNSurnameType">
<xs:sequence>
<xs:element name="Name" type="xs:string"/>
<xs:element name="Surname" type="xs:string"/>
</xs:sequence>
</xs:group>
<xs:complexType name="ResourcePersonType">
<xs:sequence>
<xs:choice>
<xs:group ref="NameNSurnameType"/>
<xs:element name="FullName" type="xs:string"/>
</xs:choice>
</xs:sequence>
</xs:complexType>
<xs:attribute name="code">
<xs:simpleType>
<xs:restriction base="xs:ID">
<xs:pattern value="CSE(d{4})"/>
</xs:restriction>
</xs:simpleType>
</xs:attribute>
<xs:complexType name="nameType">
<xs:simpleContent>
<xs:extension base="xs:string">
<xs:attribute name="shortName" type="xs:string"/>
</xs:extension>
</xs:simpleContent>
</xs:complexType>
<xs:element name="Modules">
<xs:complexType>
<xs:sequence>
<xs:element name="Module" minOccurs="1" maxOccurs="unbounded">
<xs:complexType>
<xs:sequence>
<xs:element name="Name" type="nameType"/>
<xs:element name="Level" type="xs:positiveInteger"/>
<xs:element name="ResourcePerson" type="ResourcePersonType"/>
</xs:sequence>
<xs:attribute ref="code" use="required"/>
</xs:complexType>
</xs:element>
</xs:sequence>
</xs:complexType>
</xs:element>
</xs:schema>