使用 servlet 在 eclipse 中获取上传文件名

Question

我有一个上传文件的应用程序。我需要将此文件传递到另一个程序中，但为此我只需要文件名。是否有任何简单的代码，仅使用 Java 或 servlet 过程？

while (files.hasMoreElements()) 
{ 
      name = (String)files.nextElement();
      type = multipartRequest.getContentType(name); 
      filename = multipartRequest.getFilesystemName(name); 
      originalFilename = multipartRequest.getOriginalFileName(name);  
      //extract the file extension - this can be use to reject a 
      //undesired file extension                      
      extension1 = filename.substring
            (filename.length() - 4, filename.length());
      extension2 = originalFilename.substring
            (originalFilename.length() - 4, originalFilename.length());
      //return a File object for the specified uploaded file
      File currentFile = multipartRequest.getFile(name);
      //InputStream inputStream = new BufferedInputStream
             (new FileInputStream(currentFile));
      if(currentFile == null) {
            out.println("There is no file selected!");
            return;
      }

Answer 1

apache commons-io 中有一个方法来获取文件的扩展名。还有guava Files类，带有getFileExtension方法。