我有两个类:
typedef std::shared_ptr<AdaptedWidget> window_ptr;
class WindowManager
{
public:
...
private:
std::stack<window_ptr> m_windowsStack;
}
和
class AdaptedWidget: public QWidget
{
Q_OBJECT
public:
AdaptedWidget(AdaptedWidget *parent = 0);
bool event(QEvent *event);
};
bool AdaptedWidget::event(QEvent *event)
{
if (event->type() == QEvent::NonClientAreaMouseButtonPress ||
event->type() == QEvent::MouseButtonPress)
{
qDebug() << "mainwindwo press";
}
return QWidget::event(event);
}
我需要从WindowManager
对象中获取有关AdaptedWidget
对象中发生的事件的信息,我该怎么做?
事件过滤器是完成任务的QT。
使您的WindowManager
类A类QObject
子类,并为其eventFilter()
方法提供实现。
之后,每次创建AdaptedWidget
时,请使用installEventFilter()
将WindowManager
实例作为事件过滤器安装。
class WindowManager : public QObject
{
public:
...
bool eventFilter(QObject* obj, QEvent* ev);
private:
std::stack<window_ptr> m_windowsStack;
}
和
bool WindowManager::eventFilter(QObject* obj, QEvent* ev){
AdaptedWidget* widget= qobject_cast<AdaptedWidget*>(obj);
if(ev->type == /*type of event you are interested in*/){
//you can compare widget against the stack of widgets you have
//if you want to stop widget from receiving the event you can return true
}
return false;
}
创建每个AdaptedWidget
实例时,将WindowManager
安装为事件过滤器:
AdaptedWidget* widget= new AdaptedWidget;
widget->installEventFilter(/*your WindowManager instance*/);
AdaptedWidget
类应具有指示鼠标按下的信号,例如
class AdaptedWidget : ... {
Q_OBJECT
...
public:
Q_SIGNAL void mousePress(const QPoint &);
};
bool AdaptedWidget::event(QEvent *event)
{
if (event->type() == QEvent::NonClientAreaMouseButtonPress ||
event->type() == QEvent::MouseButtonPress)
{
auto ev = static_cast<QMouseEvent*>(event);
emit mousePress(ev->pos());
qDebug() << "mainwindow press";
}
return QWidget::event(event);
}
另一种方法是使用事件过滤器,但这不必要地紧密地伴侣。