如何使用 php 过滤输出数据 JSON

Question

我有以下数据：

$data = '
[{"kode":"AX5","harga":"6200","status":"1"},
{"kode":"AX10","harga":"11250","status":"1"},
{"kode":"AX25","harga":"25750","status":"1"},
{"kode":"AX50","harga":"50800","status":"1"},
{"kode":"AX100","harga":"100600","status":"1"},
{"kode":"B25","harga":"25500","status":"1"},
{"kode":"B50","harga":"49800","status":"1"},
{"kode":"B100","harga":"99100","status":"1"},
{"kode":"B150","harga":"147850","status":"1"},
{"kode":"B200","harga":"196600","status":"1"},
{"kode":"C5","harga":"4750","status":"2"},
{"kode":"C10","harga":"9775","status":"2"},
{"kode":"C20","harga":"19850","status":"2"},
{"kode":"C50","harga":"50100","status":"2"},
{"kode":"C100","harga":"100050","status":"2"},
{"kode":"E5","harga":"5100","status":"1"},
{"kode":"E10","harga":"10425","status":"1"},
{"kode":"E25","harga":"25350","status":"1"}]'

以下代码片段返回 kode 中的所有值：

$hasil = json_decode($data);
foreach ($hasil as $hasilz) {
    echo $hasilz->kode . PHP_EOL;
}

我想过滤代码，只显示以下值（AX和C）：

AX5 AX10 AX25 AX50 AX100 
C5 C10 C20 C50 C100

任何身体都可以帮助我用foreach过滤$hasilz->kode？

Answer 1

在这里，如果您知道字符串的字符串模式和长度，请使用 substr（） 方法检查字符串的内容。

foreach ($hasil as $hasilz) {
  if(substr($hasilz->kode,0,2)=="AX"||substr($hasilz->kode,0,1)=="C"){
     echo $hasilz->kode . PHP_EOL; 
  }
}

您还可以使用$hasilz->kode[0]=='A' and $hasilz->kode[0]=='C'来检查第一个字符。
你也可以使用 strstr() — 查找字符串

Answer 2

脚本

[akshay@gold tmp]$ cat test.php
<?php
$data = '
[{"kode":"AX5","harga":"6200","status":"1"},
{"kode":"AX10","harga":"11250","status":"1"},
{"kode":"AX25","harga":"25750","status":"1"},
{"kode":"AX50","harga":"50800","status":"1"},
{"kode":"AX100","harga":"100600","status":"1"},
{"kode":"B25","harga":"25500","status":"1"},
{"kode":"B50","harga":"49800","status":"1"},
{"kode":"B100","harga":"99100","status":"1"},
{"kode":"B150","harga":"147850","status":"1"},
{"kode":"B200","harga":"196600","status":"1"},
{"kode":"C5","harga":"4750","status":"2"},
{"kode":"C10","harga":"9775","status":"2"},
{"kode":"C20","harga":"19850","status":"2"},
{"kode":"C50","harga":"50100","status":"2"},
{"kode":"C100","harga":"100050","status":"2"},
{"kode":"E5","harga":"5100","status":"1"},
{"kode":"E10","harga":"10425","status":"1"},
{"kode":"E25","harga":"25350","status":"1"}, 
{"kode":"CXX25","harga":"25350","status":"1"}]';
foreach(json_decode($data) as $hasilz) 
{
    if(preg_match("/^(AX|C)d+$/",$hasilz->kode)) 
            echo $hasilz->kode . PHP_EOL;
}
?>

输出

[akshay@gold tmp]$ php test.php
AX5
AX10
AX25
AX50
AX100
C5
C10
C20
C50
C100

Answer 3

此解决方案考虑了使用 array_filter 的更实用的范式。唉，php 本身不支持some，因此一个 foreach 是不可能轻易避免的。

<?php
$data = '[{"kode":"AX5","harga":"6200","status":"1"},
{"kode":"AX10","harga":"11250","status":"1"},
{"kode":"AX25","harga":"25750","status":"1"},
{"kode":"AX50","harga":"50800","status":"1"},
{"kode":"AX100","harga":"100600","status":"1"},
{"kode":"B25","harga":"25500","status":"1"},
{"kode":"B50","harga":"49800","status":"1"},
{"kode":"B100","harga":"99100","status":"1"},
{"kode":"B150","harga":"147850","status":"1"},
{"kode":"B200","harga":"196600","status":"1"},
{"kode":"C5","harga":"4750","status":"2"},
{"kode":"C10","harga":"9775","status":"2"},
{"kode":"C20","harga":"19850","status":"2"},
{"kode":"C50","harga":"50100","status":"2"},
{"kode":"C100","harga":"100050","status":"2"},
{"kode":"E5","harga":"5100","status":"1"},
{"kode":"E10","harga":"10425","status":"1"},
{"kode":"E25","harga":"25350","status":"1"}]';
$data = json_decode($data);
$wantedKodes = [
    'AX',
    'C',
];
$filtered = array_filter(
    $data,
    function ($object) use ($wantedKodes) {
        foreach ($wantedKodes as $kode) {
            if (strpos($object->kode, $kode) === 0) {
                return true;
            }
        }
        return false;
    }
);
foreach ($filtered as $item) {
    echo "{$item->kode} n";
}

输出将是：

AX5 
AX10 
AX25 
AX50 
AX100 
C5 
C10 
C20 
C50 
C100