考虑以下XML:
<SomeRoot>
<SomeElement>
<SomeThing>25</SomeThing>
<SomeOther>Cat</SomeOther>
</SomeElement>
<SomeElement>
<SomeThing>46</SomeThing>
<SomeOther>Dog</SomeOther>
</SomeElement>
<SomeElement>
<SomeThing>83</SomeThing>
<SomeOther>Bat</SomeOther>
</SomeElement>
<SomethingElse>Unrelated to the SomeElements above</SomethingElse>
</SomeRoot>
我想要select SomeThing where SomeOther = 'Cat'
。以下C#代码抛出一个空引用异常:
xmlDoc = new XmlDocument();
this.path = path;
// Path is passed elsewhere
Console.WriteLine(xmlDoc.SelectSingleNode("/SomeRoot/SomeElement/SomeThing[../SomeOther='Cat']").InnerText);
此处使用的正确XPath语法是什么?
您缺少加载
var xmlDoc = new XmlDocument();
xmlDoc.Load(path);
Console.WriteLine(xmlDoc.SelectSingleNode("/SomeRoot/SomeElement/SomeThing[../SomeOther='Cat']").InnerText);
以下是我所做的事情,它是有效的;
XmlDocument xDoc = new XmlDocument();
xDoc.LoadXml(@"<SomeRoot><SomeElement><SomeThing>25</SomeThing><SomeOther>Cat</SomeOther></SomeElement></SomeRoot>");
var x = xDoc.SelectSingleNode("/SomeRoot/SomeElement/SomeThing[../SomeOther= 'Cat']").InnerText;
您可以避免使用任何反向轴:
/*/SomeElement[SomeOther='Cat']/SomeThing