仅使用实例ID添加到Django Manytomanyfield

Question

当您只有ID列表时，可以添加到ManyTomanyField，而没有DB命中以检索实例(add_instances_but_with_db_hit可以做到这一点，但是hit hit hit hit hit the hit(。

谢谢。

class WorkerCombinedPayment(AbstractReimbursement):
    charge_id = models.TextField(blank=True, null=True)
    paid = models.BooleanField(default=False)
    worker = models.ForeignKey(Worker)
class MassPayment(TimeStampedModel):
    list_payments = JSONField(blank=True, null=True)
    paypal_batch_id = models.TextField(blank=True, null=True)
    success = models.NullBooleanField()
    response_from_paypal = JSONField(blank=True, null=True)
    workercombinedpayments = models.ManyToManyField(WorkerCombinedPayment)
    def add_instances_but_with_db_hit(self, id_list):
        found = WorkerCombinedPayment.objects.filter(id__in=id_list)
        self.workercombinedpayments.add(found)

Answer 1

是的，您可以通过IDS：

self.workercombinedpayments.add(*id_list)

Answer 2

facebook django python Web框架组在此主题中回答了我的问题。这是"集合"上的Django文档。NB这将替换现有内容。如果您想更新领域，而不是覆盖它，请参见 @danielroseman的接受答案。

class WorkerCombinedPayment(AbstractReimbursement):
    charge_id = models.TextField(blank=True, null=True)
    paid = models.BooleanField(default=False)
    worker = models.ForeignKey(Worker)
class MassPayment(TimeStampedModel):
    list_payments = JSONField(blank=True, null=True)
    paypal_batch_id = models.TextField(blank=True, null=True)
    success = models.NullBooleanField()
    response_from_paypal = JSONField(blank=True, null=True)
    workercombinedpayments = models.ManyToManyField(WorkerCombinedPayment)
    def add_instances(self, id_list):
        self.workercombinedpayments.set(id_list)