目标:我希望获取重新分配工作项的次数据我了解,正确的查询如下:
SELECT
WorkItemDimvw.Id,
COUNT(WorkItemAssignedToUserFactvw.WorkItemAssignedToUser_UserDimKey) AS Assignments
FROM WorkItemDimvw INNER JOIN WorkItemAssignedToUserFactvw
ON WorkItemDimvw.WorkItemDimKey = WorkItemAssignedToUserFactvw.WorkItemDimKey
GROUP BY WorkItemDimvw.Id
现有查询如下,我想知道/忘记我是否应该:
- 只需添加
COUNT(WorkItemAssignedToUserFactvw.WorkItemAssignedToUser_UserDimKey) AS Assignments
,因为联接是存在的,除了它是按 WorkItemDimvw.Id 分组
的 - 它应该改为下面的选择中的子查询吗?
查询:
SELECT
SRD.ID,
SRD.Title,
SRD.Description,
SRD.EntityDimKey,
WI.WorkItemDimKey,
IATUFact.DateKey
FROM
SLAConfigurationDimvw
INNER JOIN SLAInstanceInformationFactvw
ON SLAConfigurationDimvw.SLAConfigurationDimKey = SLAInstanceInformationFactvw.SLAConfigurationDimKey
RIGHT OUTER JOIN ServiceRequestDimvw AS SRD
INNER JOIN WorkItemDimvw AS WI
ON SRD.EntityDimKey = WI.EntityDimKey
LEFT OUTER JOIN WorkItemAssignedToUserFactvw AS IATUFact
ON WI.WorkItemDimKey = IATUFact.WorkItemDimKey
AND IATUFact.DeletedDate IS NULL
诀窍是在加入子查询之前聚合子查询上的数据。
SELECT
SRD.ID,
SRD.Title,
SRD.Description,
SRD.EntityDimKey,
WI.WorkItemDimKey,
IATUFact.DateKey,
IATUFact.Assignments
FROM
SLAConfigurationDimvw
INNER JOIN
SLAInstanceInformationFactvw
ON SLAConfigurationDimvw.SLAConfigurationDimKey = SLAInstanceInformationFactvw.SLAConfigurationDimKey
RIGHT OUTER JOIN
ServiceRequestDimvw AS SRD
ON <you're missing something here>
INNER JOIN
WorkItemDimvw AS WI
ON SRD.EntityDimKey = WI.EntityDimKey
LEFT OUTER JOIN
(
SELECT
WorkItemDimKey,
DateKey,
COUNT(WorkItemAssignedToUser_UserDimKey) AS Assignments
FROM
WorkItemAssignedToUserFactvw
WHERE
DeletedDate IS NULL
GROUP BY
WorkItemDimKey,
DateKey
)
IATUFact
ON WI.WorkItemDimKey = IATUFact.WorkItemDimKey