Next Line Javascript

Question

我的代码中是什么导致打印的代码出现在下一行？

function GetSelected (selectTag) {
    var selIndexes = "";
    for (var i = 0; i < selectTag.options.length; i++) {
        var optionTag = selectTag.options[i];
        if (optionTag.selected) {
            if (selIndexes.length > 0)
                selIndexes += "";
            selIndexes = optionTag.value;
        }
    }
    var info = document.getElementById ("info");
    if (selIndexes.length > 0) {
        info.innerHTML = selIndexes;
    }
    else {
        info.innerHTML = "There is no selected option";
    }
}

这是组合框中的选项之一：

<select option="single"  name= "viocat" id="viocat" onchange="GetSelected (this);" class = "form-control">
    <option>Choose category ...</option>
    <option value="<?php
        $con = mysqli_connect("///") or die (mysql_error());
        $sql = mysqli_query ($con, "SELECT violationcategory, MAX(code) AS highest_id FROM tbl_violation where violationcategory = 'rn DL'");
        $sql = "SELECT violationcategory, MAX(code) AS highest_id FROM tbl_violation where violationcategory = 'rn OR'";
        $result = mysql_query ($sql,$con);
        while($row = mysql_fetch_array($result)){
            $i = $row['highest_id'];
            $i++;
            echo "OR - " .$i;
        }
    ?> "> Driver's License Related</option>
</select>

以下是显示位置：

 <label type= "text" id="info" name="viocode" class = "form-control"> 

Answer 1

我不太确定下一行的确切含义，但是，从您删除的部分问题来看，我认为这是因为您在新行上开始了PHP块。而不是：

<option>Choose category ...</option>
    <option value="
 <?php

尝试：

<option>Choose category ...</option>
    <option value="<?php