我正在努力处理 httpwebrequest 中的超时错误等,但它在调试中不断抛出错误,这意味着我无法在我的应用程序中显示状态码。我尝试使用尝试捕获,但是当我尝试获取响应后状态代码时。我唯一能从 catch 中得到的是我在调试中看到的错误描述,而不是响应的状态代码。
更新:(我最终这样做了。我仍然无法获得不同的状态代码,但我想这会起作用(
Try
postresponse = DirectCast(postreq.GetResponse, HttpWebResponse)
Dim postreqreader As New StreamReader(postresponse.GetResponseStream())
data = postreqreader.ReadToEnd
'Get title
Dim reg = New Regex("<title>(.*?)</title>")
Dim matches = reg.Matches(data)
Dim wtitle As String = "No title"
For Each mat As Match In matches
wtitle = mat.Value.Replace("<title>", "").Replace("</title>", "")
Next mat
ListView1.Items(ci).SubItems(3).Text = wtitle
'OK
ListView1.Items(ci).SubItems(1).Text = "OK"
Catch ex As Exception When WebExceptionStatus.Timeout
ListView1.Items(ci).SubItems(1).Text = "Timeout"
Catch ox As Exception When WebExceptionStatus.NameResolutionFailure
MsgBox("Name resolution failure")
End Try
源语言:
Dim data As String = Nothing
Try
Dim postreq As HttpWebRequest = DirectCast(HttpWebRequest.Create(url), HttpWebRequest)
postreq.Method = "GET"
postreq.KeepAlive = True
postreq.Timeout = 5000 '10s
postreq.UserAgent = "Mozilla/5.0 (Windows; U; Windows NT 6.1; ru; rv:1.9.2.3) Gecko/20100401 Firefox/4.0 (.NET CLR 3.5.30729"
postreq.ContentType = "application/x-www-form-urlencoded"
postreq.Referer = "https://www.facebook.com"
Dim postresponse As HttpWebResponse
postresponse = DirectCast(postreq.GetResponse, HttpWebResponse)
If postresponse.StatusCode = HttpStatusCode.OK Then
Dim postreqreader As New StreamReader(postresponse.GetResponseStream())
data = postreqreader.ReadToEnd
'Get title
Dim reg = New Regex("<title>(.*?)</title>")
Dim matches = reg.Matches(data)
Dim wtitle As String = "No title"
For Each mat As Match In matches
wtitle = mat.Value.Replace("<title>", "").Replace("</title>", "")
Next mat
ListView1.Items(ci).SubItems(3).Text = wtitle
'OK
ListView1.Items(ci).SubItems(1).Text = "OK"
Else
ListView1.Items(ci).SubItems(1).Text = "Fejl"
End If
Catch ex As Exception
MsgBox(ex.ToString)
End Try
ex
异常对象是泛型Exception
类型,不提供任何特定于 HttpWebRequest 的信息。为WebException
对象添加捕获块:
Try
' ..........
Catch ex As WebException
If ex.Status = WebExceptionStatus.Timeout Then
MsgBox("The request has timed out!")
Else
MsgBox(ex.Status)
End If
Catch ex As Exception
MsgBox(ex.ToString)
End Try