ANTLRErrorListener to get error msg

Question

我试图从 ANTLR 获取错误消息，但我很困惑

我替换了标准错误侦听器，就像这个参考问题一样

public String runAntlr(String sqlFile){
    ANTLRErrorListener error = new BaseErrorListener();
    ANTLRInputStream input;
    try {
        input = new ANTLRFileStream(sqlFile);
    } catch (Exception e) {
        return e.toString();
    }
    tsqlLexer lexer = new tsqlLexer(input);
    CommonTokenStream tokens = new CommonTokenStream(lexer);
    tsqlParser parser = new tsqlParser(tokens);
    parser.removeErrorListeners();
    lexer.removeErrorListeners();
    parser.addErrorListener(error);
    lexer.addErrorListener(error);
    ParseTree tree = parser.tsql_file();
    new MyTsqlVisitor().visit(tree);
    System.out.println(error);
    return "Analysis successful";
}

这是运行后控制台中的文本：

run:
line 2:16 mismatched input 'as' expecting '.'
line 2:19 no viable alternative at input 'date'
line 5:38 mismatched input 'where' expecting {EXCEPT, INTERSECT, UNION, ')'}
BUILD SUCCESSFUL (total time: 5 seconds)

添加ANTLRErrorListener后

run:
org.antlr.v4.runtime.BaseErrorListener@4507ed
BUILD SUCCESSFUL (total time: 4 seconds)

我是否正确实施了ANTLRErrorListener？

Answer 1

它现在可以工作了，这是我的解决方案：

首先，我的MyAntlrErrorListener实现：

public static MyAntlrErrorListener INSTANCE = new MyAntlrErrorListener();
//When the value is false, the syntaxError method returns without displaying errors.
private static final boolean REPORT_SYNTAX_ERRORS = true;
private String errorMsg = "";
@Override
public void syntaxError(Recognizer<?, ?> recognizer, 
                        Object offendingSymbol, 
                        int line, 
                        int charPositionInLine, 
                        String msg, 
                        RecognitionException re) {
    if (!REPORT_SYNTAX_ERRORS) {
        return;
    }
    String sourceName = recognizer.getInputStream().getSourceName();
    if (!sourceName.isEmpty()) {
        sourceName = String.format("%s:%d:%d: ", sourceName, line, charPositionInLine);
    }
    System.err.println(sourceName+"line "+line+":"+charPositionInLine+" "+msg);
    errorMsg = errorMsg + "n" + sourceName+"line "+line+":"+charPositionInLine+" "+msg;
}
@Override
public String toString() {
    return errorMsg;
}    

我在我的主类中得到错误Msg，如下所示：

...
lexer.removeErrorListeners();
lexer.addErrorListener(MyAntlrErrorListener.INSTANCE);
parser.removeErrorListeners();
parser.addErrorListener(MyAntlrErrorListener.INSTANCE);
...
return MyAntlrErrorListener.INSTANCE.toString();