创建Oracle包主体时出错



我的包中有以下主体,用于在HR模式中执行一些CRUD操作:

CREATE SEQUENCE emp_sequence;
CREATE OR REPLACE PACKAGE BODY employee_crud AS
   PROCEDURE create_emp(p_last_name IN employees.last_name%type, p_first_name IN    employees.first_name%type, 
                             p_email IN employees.email%type, p_hire_date IN  employees.hire_date%type, 
                             p_job_id IN employees.job_id%type) AS

   BEGIN
     SELECT emp_sequence.NEXTVAL INTO id FROM dual;
     INSERT INTO employees(last_name, first_name, email, hire_date, job_id)
     VALUES (emp_seq.nextval, p_last_name, p_first_name, p_email, p_hire_date, p_job_id);
   EXCEPTION
   WHEN DUP_VAL_ON_INDEX THEN
     dbms_output.put_line('error');
   END create_emp;

   PROCEDURE erase_emp(p_employee_id IN employees.employee_id%type) AS
   BEGIN
     DELETE FROM employees
     WHERE employee_id = p_employee_id;
   EXCEPTION
   WHEN  NO_DATA_FOUND THEN
     dbms_output.put_line('Error');
   END erase_emp;

   PROCEDURE upd_emp(p_employee_id IN employees.employee_id%type, p_salary IN  employees.salary%type, 
                                  p_email IN employees.email%type, p_department_id IN  employees.department_id%type) AS
   BEGIN
     UPDATE employees
     SET  employee_id = p_employee_id,
          salary = p_salary,
          email = p_email,
          department_id = p_department_id
     WHERE employee_id = p_employee_id;
   EXCEPTION
   WHEN NO_DATA_FOUND THEN
     dbms_output.put_line('error');
   END upd_emp;

   PROCEDURE read_emp(p_employee_id IN employees.employee_id%type, p_last_name OUT  employees.last_name%type, 
                                 p_first_name OUT employees.first_name%type, p_email OUT  employees.email%type, 
                                 p_hire_date OUT  employees.hire_date%type, p_job_id OUT  employees.job_id%type, 
                                 p_salary OUT employees.salary%type) AS
   BEGIN
     SELECT employee_id, last_name, first_name, email, hire_date, job_id, salary
     INTO  p_last_name, p_first_name, p_email, p_hire_date, p_job_id, p_salary
     FROM EMPLOYEES
     WHERE employee_id = p_employee_id;
   EXCEPTION
   WHEN NO_DATA_FOUND THEN
     dbms_output.put_line('Error');
   END read_emp;
END employee_crud;
/

在创建规范(这是正确的)之后,我创建了一个序列来帮助添加员工。但是在编译包的主体时,它显示了以下错误:

LINE/COL ERROR
-------- ----------------------------------------------------
10/5     PL/SQL: SQL Statement ignored
10/38    PLS-00201: 'ID' must be declared
10/41    PL/SQL: ORA-00904: : identifier is not valid
11/5     PL/SQL: SQL Statement ignored
11/17    PL/SQL: ORA-00913: too many values
49/5     PL/SQL: SQL Statement ignored
51/5     PL/SQL: ORA-00947: insufficient values

我应该怎么做才能纠正这些错误?我更改了代码中的一些名称,因为这是一项任务,我很难在没有错误的情况下完成。

10/38    PLS-00201: 'ID' must be declared

您正在将数据选择到尚未声明的局部变量ID中。如果您想声明一个局部变量,您可以在ASBEGIN 之间的声明部分中这样做

   PROCEDURE create_emp(p_last_name IN employees.last_name%type, 
                        p_first_name IN    employees.first_name%type, 
                        p_email IN employees.email%type, 
                        p_hire_date IN  employees.hire_date%type, 
                        p_job_id IN employees.job_id%type) 
   AS
     id integer;
   BEGIN
     SELECT emp_sequence.NEXTVAL INTO id FROM dual;

如果要执行此操作,则需要在INSERT语句中使用局部变量id,而不是直接调用emp_sequence.nextval。不过,就我个人而言,我会去掉局部变量,去掉初始的SELECT,然后在INSERT语句中调用emp_sequence.nextval

11/17    PL/SQL: ORA-00913: too many values

不过,无论如何操作,都需要INSERT中的列数与指定的VALUES的列数相匹配。

   PROCEDURE create_emp(p_last_name IN employees.last_name%type, 
                        p_first_name IN    employees.first_name%type, 
                        p_email IN employees.email%type, 
                        p_hire_date IN  employees.hire_date%type, 
                        p_job_id IN employees.job_id%type) 
   AS
     id integer;
   BEGIN
     SELECT emp_sequence.NEXTVAL INTO id FROM dual;
     INSERT INTO employees(employee_id, last_name, first_name, email, hire_date, job_id)
       VALUES (id, p_last_name, p_first_name, p_email, p_hire_date, p_job_id);
  END create_emp;

或者如果你想直接调用序列

   PROCEDURE create_emp(p_last_name IN employees.last_name%type, 
                        p_first_name IN    employees.first_name%type, 
                        p_email IN employees.email%type, 
                        p_hire_date IN  employees.hire_date%type, 
                        p_job_id IN employees.job_id%type) 
   AS
   BEGIN
     INSERT INTO employees(employee_id, last_name, first_name, email, hire_date, job_id)
       VALUES ( emp_sequence.NEXTVAL, p_last_name, p_first_name, p_email, p_hire_date, p_job_id);
  END create_emp;

同样,对于您的下一个错误,您提取的变量数量应该与您选择的列数量相匹配

51/5     PL/SQL: ORA-00947: insufficient values

在read_emp中,您选择了7个内容,并试图将它们放入6个变量中。假设你不想返回employee_id,就不用麻烦选择它。

   PROCEDURE read_emp(p_employee_id IN employees.employee_id%type, 
                      p_last_name OUT  employees.last_name%type, 
                      p_first_name OUT employees.first_name%type, 
                      p_email OUT  employees.email%type, 
                      p_hire_date OUT  employees.hire_date%type, 
                      p_job_id OUT  employees.job_id%type, 
                      p_salary OUT employees.salary%type) 
   AS
   BEGIN
     SELECT last_name, first_name, email, hire_date, job_id, salary
     INTO  p_last_name, p_first_name, p_email, p_hire_date, p_job_id, p_salary
     FROM EMPLOYEES
     WHERE employee_id = p_employee_id;
   END read_emp;

虽然您可以像这样编写read_emp过程,但通常创建一个返回employees%rowtype记录的函数会更有意义。

应该删除您的例外条款。充其量,他们是在丢弃错误堆栈,它会告诉人们什么失败了,在哪里失败了。最坏的情况是,它们隐藏了错误(你永远不应该认为任何人都会看到你写给dbms_output的任何东西),并导致调用代码相信某个操作成功了,但它没有成功。

最新更新