尝试用C访问Twitter流媒体API

Question

我从C libcurl得到输出成字符串的代码。我修改了它，我想用它来访问Twitter流。我在代码中添加了curl_easy_setopt(curl, CURLOPT_URL, "http://stream.twitter.com/1/statuses/sample.json");和curl_easy_setopt(curl, CURLOPT_USERPWD, "neilmarion:my_password");。但问题是无论何时执行它，都没有输出。一定是什么问题?谢谢。

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <curl/curl.h>
struct string {
  char *ptr;
  size_t len;
};
void init_string(struct string *s) {
  s->len = 0;
  s->ptr = malloc(s->len+1);
  if (s->ptr == NULL) {
    fprintf(stderr, "malloc() failedn");
    exit(EXIT_FAILURE);
  }
  s->ptr[0] = '';
}
size_t writefunc(void *ptr, size_t size, size_t nmemb, struct string *s)
{
  size_t new_len = s->len + size*nmemb;
  s->ptr = realloc(s->ptr, new_len+1);
  if (s->ptr == NULL) {
    fprintf(stderr, "realloc() failedn");
    exit(EXIT_FAILURE);
  }
  memcpy(s->ptr+s->len, ptr, size*nmemb);
  s->ptr[new_len] = '';
  s->len = new_len;
  return size*nmemb;
}
int main(void)
{
  CURL *curl;
  CURLcode res;
  curl = curl_easy_init();
  if(curl) {
    struct string s;
    init_string(&s);
    curl_easy_setopt(curl, CURLOPT_URL, "http://stream.twitter.com/1/statuses/sample.json");
    curl_easy_setopt(curl, CURLOPT_USERPWD, "neilmarion:my_password");
    curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, writefunc);
    curl_easy_setopt(curl, CURLOPT_WRITEDATA, &s);
    res = curl_easy_perform(curl);
    printf("%sn", s.ptr);
    free(s.ptr);
    /* always cleanup */
    curl_easy_cleanup(curl);
  }
  return 0;
}

Answer 1

最快的下一步可能是设置CURLOPT_HEADER，以便在正文输出中包含标题。最有可能的是，我猜它在安全性方面失败了，您将在标题中看到详细信息。