class Process
{
static void Main(string[] args)
{
int threads = 0;
int processes = 0;
Console.WriteLine("Total number of processes:");
processes = Convert.ToInt32(Console.ReadLine());
Console.WriteLine("Enter number of parallel threads:");
threads = Convert.ToInt32(Console.ReadLine());
ManualResetEvent[] events = new ManualResetEvent[threads];
int k = 0, innercount = 0;
//----running in bunches
do
{
for (int l = 0; l < threads; l++)
{
if (k < threads)
{
events[l] = new ManualResetEvent(false);
Runner r = new Runner(events[l], innercount);
new Thread(new ThreadStart(r.Run)).Start();
Console.WriteLine("running start...{0}", innercount);
k++;
innercount++;
}
}
WaitHandle.WaitAny(events);
k--;
Console.WriteLine("Decrement counter...{0}", k);
}
while (innercount < processes);
WaitHandle.WaitAll(events);
Console.WriteLine("All finished!");
Console.ReadLine();
}
}
class Runner
{
static readonly object rngLock = new object();
static Random rng = new Random();
ManualResetEvent ev;
int id;
internal Runner(ManualResetEvent ev, int id)
{
this.ev = ev;
this.id = id;
}
internal void Run()
{
int sleepTime;
lock (rngLock)
{
sleepTime = rng.Next(2000);
}
Thread.Sleep(sleepTime);
Console.WriteLine("Thread Runner {0}",
id);
if (ev.Set())
{
Console.WriteLine("release thread...{0}", id);
}
}
}
我必须运行多个线程。如果一个线程结束,那么启动另一个线程。问题是它同时启动了所有的进程。(似乎这个条件不工作好waitthandle . waitany(事件);)
1:如果有20个线程在运行,那么当第20个线程释放1个线程时,将启动第21个线程。
2:不使用线程池,可以使用EventWaitHandler。
你可以用PLinq和WithDegreeOfParallelism
做点什么。
WithDegreeOfParallelism
将限制同时运行的线程数。
下面的例子展示了如何使用Plinq以有限的并行度运行多个worker,并向每个worker传递一个不同的对象。
它假设您从一个对象序列开始,并且您希望将每个对象传递给一个工作方法:
using System;
using System.Collections.Generic;
using System.Linq;
using System.Threading;
namespace Demo
{
class DataForWorker
{
public int ID;
public string Value;
};
class Program
{
Random rng = new Random();
int numberOfThreadsRunning;
void Run()
{
int maxThreads = 8;
IEnumerable<DataForWorker> dataForWorkers = getDataForWorkers();
dataForWorkers
.AsParallel()
.WithDegreeOfParallelism(maxThreads)
.ForAll(worker);
}
IEnumerable<DataForWorker> getDataForWorkers()
{
// Just return some dummy data.
int numberOfDataItems = 30;
return Enumerable.Range(1, numberOfDataItems).Select
(
n => new DataForWorker
{
ID = n,
Value = n.ToString()
}
);
}
void worker(DataForWorker data)
{
int n = Interlocked.Increment(ref numberOfThreadsRunning);
Console.WriteLine("Thread " + data.ID + " is starting. #threads now = " + n);
Thread.Sleep(rng.Next(1000, 2000));
Console.WriteLine("Thread " + data.ID + " is stopping.");
Interlocked.Decrement(ref numberOfThreadsRunning);
}
static void Main()
{
new Program().Run();
}
}
}
尝试使用信号量来控制线程的释放。看看这个例子。但是我想知道为什么你不能用ThreadPool
来完成这个?
每次线程进入时,信号量的计数递减信号量,并在线程释放该信号量时递增。当计数为零,后续请求阻塞,直到其他线程释放信号量。当所有线程都释放了信号量时,计数处于信号量失效时指定的最大值创建。
这样,一旦一个线程释放了信号量中的一个槽位,另一个线程就可以占用这个槽位并运行。