我看过servlet的例子,它们是这样的:
public void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
PrintWriter out = response.getWriter();
out.println("<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">");
...
}
我的问题是,而不是代码,我可以返回一个HTML页面吗?我的意思是,像这样:
public void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
PrintWriter out = response.getWriter();
SHOW(FILE.HTML);
}
谢谢! !div;)
有几种不同的方法可以做到这一点:
将servlet转发到HTML文件所在的路径。比如:
RequestDispatcher rd = request.getRequestDispatcher("something.html"); rd.forward(request, response);
发送重定向到HTML所在的URL。比如:
response.sendRedirect("something.html");
读取HTML文件的内容,然后将HTML文件的内容写入servlet的printwwriter。