根据密钥提取列表

Question

我有一个记录

["name1":["value1":10, "value2":name1, "value3":150, "value4":20],
 "name2":["value1":10, "value2":name2, "value3":150, "value4":20]]

我有一个列表，其中的值是name1, name2等

我想根据的名称1提取列表

["name1":["value1":10, "value2":name1, "value3":150, "value4":20]]

subMap（["name1"]）确实对我有用，但我有一个列表，通过循环该列表，我需要提取值

Ex : namesList.each{record ->
          newMap = firstmap.subMap(record)
     }

Answer 1

使用subMap（集合密钥）:

def map = ["name1":["value1":10, "value2":"name1", "value3":150, "value4":20],
           "name2":["value1":10, "value2":"name2", "value3":150, "value4":20]]
//Answer here, return Map still:
println map.subMap("name1")
//Or
println map.subMap(["name1", "name2"])