如何通过与 django 中的某些属性的关系来查询 ManyToMany


class Person(models.Model):
    age = models.IntegerField()
class Group(models.Model):
    people = models.ManyToManyField(Person,through=Membership)
class Membership(models.Model):
    person = models.ForeignKey(Person)
    group = models.ForeignKey(Group)
    existing = models.BooleanField()

这是简化的类结构,我想查询的是:组上的查询集,以便有一些人具有成员身份,因此existing为真。我尝试使用Group.objects.filter(membership__existing=True)但它似乎抓住了所有组。

筛选出查询集的最有效方法是什么?

我使用您的模型定义创建了一个示例应用,您指定的筛选器工作正常。我不得不将people字段的 through 属性更改为字符串,因为尚未定义Membership。我还在Group中添加了一个名称字段,以便于测试。

class Person(models.Model):
    age = models.IntegerField()
class Group(models.Model):
    name = models.CharField(max_length=255)
    people = models.ManyToManyField(Person, through='Membership')
class Membership(models.Model):
    person = models.ForeignKey(Person)
    group = models.ForeignKey(Group)
    existing = models.BooleanField()

然后在控制台中:

>>> p1 = Person.objects.create(age=10)
>>> p2 = Person.objects.create(age=20)
>>> has_existing = Group.objects.create(name='has_existing')
>>> has_non_existing = Group.objects.create(name='has_non_existing')
>>> has_none = Group.objects.create(name='has_none')
>>> Membership.objects.create(person=p1, group=has_existing, existing=True)
>>> Membership.objects.create(person=p2, group=has_non_existing, existing=False)
>>> existing = Group.objects.filter(membership__existing=True)
>>> assert(len(existing) == 1)
>>> assert(existing[0].name == 'has_existing')

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