我创建了一段代码，玩家可以在其中四处寻找宝藏。当玩家降落在宝藏上时，会增加10个硬币，而如果玩家降落在地精上，则会扣除所有硬币。我为这个"钱"创建了一个函数，尽管它似乎不起作用。每当我运行代码时，money函数似乎什么都不起作用。请任何人编辑我的代码使其工作，或者提供任何建议，谢谢。这是我的代码：
import time
from random import *
# Set up Initial Variables
Money = 0
grid = []
character = "X"
# player_loc will hold the x, y location of the player
player_loc = (0, 0)
# These are a mapping of direction
NORTH = "N"
SOUTH = "S"
EAST = "E"
WEST = "W" #All variables used for Later on
Treasure = "T"
Goblin = "G"
def menu(): #functiom
c = input(" To quit this program, type 'quit' To start the game, type 'start'")#Users choice to start game
if c == "quit":
exit()
elif c == "start": #If users input is to start the game the all of this appears
print("Welcome to the treasure hunt game!")
time.sleep(1)
print(" ")
print("These are the rules! You have a choice of a grid ranging from a 3x3 choice to a 20x20 choice")
print(" ")
time.sleep(2)
print("in these grids, bandits and treasure chests will spawn at random locations, hidden to you.")
print(" ")
time.sleep(3)
print("You will have a choice of the amount of goblins and treasures you would like to spawn in, ranging from 1-20.")
print(" ")
time.sleep(3)
print("You will move around the map, in search of treasures which will give you 10 gold. Although landing on a goblin would deduct the amount of gold to 0.")
print(" ")
time.sleep(3)
print("Furthurmore, just deciding on a position you would like to move to, would give you an extra 1 piece of gold.")
print(" ")
time.sleep(3)
print("You can only find the same treasure chest two times before it's replaced by a bandit.")
print(" ")
time.sleep(3)
print("To check the amount of gold you have and the amount of bandits and treasure chests in the grid. Simply type 'status'")
print(" ")
time.sleep(3)
print("Don't forget! If you have collected all the treasure chests and you don't have 100 gold, you lose the game!")
print(" ")
time.sleep(3)
print("Good luck, you will now be entered into the game")
print(" ")
time.sleep(2)
x = input("What is your name?")
username = x
time.sleep(2)
print ("Hello,", username,"! Let's jump into the game!")
setupGrid()
Chests_and_Goblins()
def setupGrid(): #New function for creating grid
global grid #Adding/creating global variables
global row
global N
N = input("How big would you like the grid to be?") #User input
time.sleep(2)
while int(N) > 20 : #Changing N to an integer so computer understamds
N =input("That number is too high or too low, The grid has to be at a size of under 20x20. Or 3x3 and larger. Please try again")
else:
while int(N) < 3 : # Asking the user to input again as number is too high or low
N = input("That number is too low, the grid has to be a size of over 3x3. Please try again")
for x in range(0, (int(N))):#For everything in range N
row = [] #The N amount of rows are created
for y in range(0, (int(N))): #For everything in range N
if x == player_loc[0] and y == player_loc[1]: #If the positions is equal to th player location
row.append(character) # Add the character in
else:
row.append('O') #Add the same amount of 0's as N
grid.append(row)
def Chests_and_Goblins():
global z
global grid
global row
global N
global Treasure
print("How many chests would you like in the grid?")
time.sleep(2)
B = input("The amount of chests you like is given by the amount of C's")
print("How many Bandits would you like in the grid?")
time.sleep(2)
F = input("The amount of Bandits you like is given by the amount of B's")
for each in B:
grid[randint(0, int(N)-1)][randint(0, int(N)-1)] = Treasure
for each in F:
grid[randint(0, int(N)-1)][randint(0, int(N)-1)] = Goblin
def moveSouth(n):
global player_loc
grid[player_loc[0]][player_loc[1]] = "O"
grid[player_loc[0] + n][player_loc[1]] = character
player_loc = (player_loc[0] + n, player_loc[1])
money()
def moveNorth(n):
global player_loc
grid[player_loc[0]][player_loc[1]] = "O"
grid[player_loc[0] - n][player_loc[1]] = character
player_loc = (player_loc[0] - n, player_loc[1])
money()
def moveEast(n):
global player_loc
grid[player_loc[0]][player_loc[1]] = "O"
grid[player_loc[0]][player_loc[1] + n] = character
player_loc = (player_loc[0], player_loc[1] + n)
money()
def moveWest(n):
global player_loc
grid[player_loc[0]][player_loc[1]] = "O"
grid[player_loc[0]][player_loc[1] - n] = character
player_loc = (player_loc[0], player_loc[1] - n)
money()
def gridRunner():
while True:
for row in grid:
print (row)
switch = {NORTH : moveNorth,
SOUTH : moveSouth,
EAST : moveEast,
WEST : moveWest }
print (" ")
time.sleep(2)
P = input("What direction would you like to move in? North (N), South(S), East(E) or West(W)?").upper()
if P not in switch:
print ("invalid move")
continue
distance = int(input("How far would you like to move in this direction? (blocks are the units)"))
switch[P](distance)
def money():
global player_loc
global character
global Treasure
if player_loc == Treasure:
print("Well done, You have gained coins")
else:
print ("You got nothing")
menu()
gridRunner()
您的money函数甚至不存储/操作money变量>。>
它只是根据"if"条件打印输出。难道不应该是这样的吗：
if player_loc == Treasure:
print("Well done, You have gained coins")
Money += 10
else:
print ("You got nothing")
Money = 0
我有一个工作代码，但这类东西最好自己做，所以我只想在这里放置一些函数，可以为您指明正确的方向：
def money(x, y):
global MONEY
if GRID[x][y] == TREASURE: MONEY += 10; print 'You found a treasure'
elif GRID[x][y] == GOBLIN: MONEY = 0; print 'You lost your money'
这个货币函数将检查网格中给定的位置，如果这是应该用货币做的事情，正如你所看到的，我们使用全局值，因为我们要修改全局值的值，我们通过x，y而不使用我们的位置的原因将在下一个函数中显而易见：
def move_west():
global GRID, POSITION
x, y = POSITION[0], POSITION[1]
if y != 0:
money(x, y-1)
GRID[x][y], GRID[x][y-1] = EMPTY, AVATAR
POSITION = (x, y-1)
else: print 'You've hit a wall'
正如你在这个函数中看到的，首先我们从一个全局值中获得当前位置，在我的例子中，这个值是一个元组（x，y）。我们检查我们移动的方式是否有效，然后在改变它之前，我们用我们的未来头寸调用货币函数，我们这样做的原因是，现在的价值可以是EMPTY、TREASURE或GOBLIN，但在我们移动之后，肯定会是AVTAR，所以我们会改变它，我们的货币函数永远看不到是否有什么可做的。调用money函数后，我们会更新网格和角色在全局变量中的位置。希望这能对你有所帮助。