我正在回答这个问题 对单个表的日期、整数和字符串数据类型字段执行多列搜索？ 并且此方法必须在 Java 8 中返回类型为 Specification
实际上，我想在关联实体内进行搜索，以及全局搜索的一部分。使用JPA 2 Specifications API可以吗？
我已经Employee并Department@OneToMany bi-directional关系。
员工.java
@Data
@Builder
@AllArgsConstructor
@NoArgsConstructor
@Entity
public class Employee implements Serializable {
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "EMPLOYEE_ID")
private Long employeeId;
@Column(name = "FIRST_NAME")
private String firstName;
@Column(name = "LAST_NAME")
private String lastName;
@Column(name = "EMAIL_ID")
private String email;
@Column(name = "STATUS")
private String status;
@Column(name = "BIRTH_DATE")
private LocalDate birthDate;
@Column(name = "PROJECT_ASSOCIATION")
private Integer projectAssociation;
@Column(name = "GOAL_COUNT")
private Integer goalCnt;
@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name = "DEPT_ID", nullable = false)
@JsonIgnore
private Department department;
}
部门.java
@Data
@Builder
@AllArgsConstructor
@NoArgsConstructor
@Entity
public class Department implements Serializable {
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "DEPT_ID")
private Long departmentId;
@Column(name = "DEPT_NAME")
private String departmentName;
@Column(name = "DEPT_CODE")
private String departmentCode;
@OneToMany(fetch = FetchType.LAZY, mappedBy = "department")
@JsonIgnore
private Set<Employee> employees;
}
我保存了如下所示的数据。我的分页应用程序.java
@SpringBootApplication
public class MyPaginationApplication implements CommandLineRunner {
public static void main(String[] args) {
SpringApplication.run(MyPaginationApplication.class, args);
}
@Autowired
private EmployeeRepository employeeRepository;
@Autowired
private DepartmentRepository departmentRepository;
@Override
public void run(String... args) throws Exception {
saveData();
}
private void saveData() {
Department department1 = Department.builder()
.departmentCode("AD")
.departmentName("Boot Depart")
.build();
departmentRepository.save(department1);
Employee employee = Employee.builder().firstName("John").lastName("Doe").email("john.doe@gmail.com")
.birthDate(LocalDate.now())
.goalCnt(1)
.projectAssociation(2)
.department(department1)
.build();
Employee employee2 = Employee.builder().firstName("Neha").lastName("Narkhede").email("neha.narkhede@gmail.com")
.birthDate(LocalDate.now())
.projectAssociation(4)
.department(department1)
.goalCnt(2)
.build();
Employee employee3 = Employee.builder().firstName("John").lastName("Kerr").email("john.kerr@gmail.com")
.birthDate(LocalDate.now())
.projectAssociation(5)
.department(department1)
.goalCnt(4)
.build();
employeeRepository.saveAll(Arrays.asList(employee, employee2, employee3));
}
}
员工控制.java
@GetMapping("/employees/{searchValue}")
public ResponseEntity<List<Employee>> findEmployees(@PathVariable("searchValue") String searchValue) {
List<Employee> employees = employeeService.searchGlobally(searchValue);
return new ResponseEntity<>(employees, HttpStatus.OK);
}
员工规格.java
public class EmployeeSpecification {
public static Specification<Employee> textInAllColumns(Object value) {
return (root, query, builder) -> builder.or(root.getModel().getDeclaredSingularAttributes().stream()
.filter(attr -> attr.getJavaType().equals(value.getClass()))
.map(attr -> map(value, root, builder, attr))
.toArray(Predicate[]::new));
}
private static Object map(Object value, Root<?> root, CriteriaBuilder builder, SingularAttribute<?, ?> a) {
switch (value.getClass().getSimpleName()) {
case "String":
return builder.like(root.get(a.getName()), getString((String) value));
case "Integer":
return builder.equal(root.get(a.getName()), value);
case "LocalDate":
return builder.equal(root.get(a.getName()), value);//date mapping
default:
return null;
}
}
private static String getString(String text) {
if (!text.contains("%")) {
text = "%" + text + "%";
}
return text;
}
}
当我点击/employees/{searchValue}时，我希望搜索与Employee表一起Department表中进行(可能正在使用类似Joins(。这可能吗？如果是，我们该怎么做？
或：这会是像这里一样的好方法吗？从使用@Query获得参考
@Query("SELECT t FROM Todo t WHERE " +
"LOWER(t.title) LIKE LOWER(CONCAT('%',:searchTerm, '%')) OR " +
"LOWER(t.description) LIKE LOWER(CONCAT('%',:searchTerm, '%'))")
List<Todo> findBySearchTerm(@Param("searchTerm") String searchTerm);
有什么指示吗？
如果你看看我的帖子，实际上我有一个加入的解决方案
@Override
public Specification<User> getFilter(UserListRequest request) {
return (root, query, cb) -> {
query.distinct(true); //Important because of the join in the addressAttribute specifications
return where(
where(firstNameContains(request.search))
.or(lastNameContains(request.search))
.or(emailContains(request.search))
)
.and(streetContains(request.street))
.and(cityContains(request.city))
.toPredicate(root, query, cb);
};
}
private Specification<User> firstNameContains(String firstName) {
return userAttributeContains("firstName", firstName);
}
private Specification<User> lastNameContains(String lastName) {
return userAttributeContains("lastName", lastName);
}
private Specification<User> emailContains(String email) {
return userAttributeContains("email", email);
}
private Specification<User> userAttributeContains(String attribute, String value) {
return (root, query, cb) -> {
if(value == null) {
return null;
}
return cb.like(
cb.lower(root.get(attribute)),
containsLowerCase(value)
);
};
}
private Specification<User> cityContains(String city) {
return addressAttributeContains("city", city);
}
private Specification<User> streetContains(String street) {
return addressAttributeContains("street", street);
}
private Specification<User> addressAttributeContains(String attribute, String value) {
return (root, query, cb) -> {
if(value == null) {
return null;
}
ListJoin<User, Address> addresses = root.joinList("addresses", JoinType.INNER);
return cb.like(
cb.lower(addresses.get(attribute)),
containsLowerCase(value)
);
};
}
private String containsLowerCase(String searchField) {
return "%" + searchField.toLowerCase() + "%";
}
在这里，您可以看到我如何按地址列(城市和街道(搜索用户。
编辑：您也不能动态地使用@Query注释(您可以动态地插入参数值，但不能插入参数。这就是Specificaion很方便的地方(
EDIT2：我知道这不是2.x.x Spring版本，而是1.5.x，但连接的想法是一样的。