如何使用aubio产生与librosa相同的mfcc结果

Question

我正在尝试用C++计算Mfcc特性。我找到了奥比奥(https://github.com/aubio/aubio)但我不能产生和Python的Librosa相同的结果(这很重要(。Librosa代码：

X, sample_rate = sf.read(file_name, dtype='float32')
mfccs = librosa.feature.mfcc(y=X, sr=sample_rate, n_mfcc=40)

Aubio代码：

#include "utils.h"
#include "parse_args.h"
#include <stdlib.h>
aubio_pvoc_t *pv;    // a phase vocoder
cvec_t *fftgrain;    // outputs a spectrum
aubio_mfcc_t * mfcc; // which the mfcc will process
fvec_t * mfcc_out;   // to get the output coefficients
uint_t n_filters = 128;
uint_t n_coefs = 40;
void process_block (fvec_t *ibuf, fvec_t *obuf)
{
fvec_zeros(obuf);
//compute mag spectrum
aubio_pvoc_do (pv, ibuf, fftgrain);
//compute mfccs
aubio_mfcc_do(mfcc, fftgrain, mfcc_out);
}
void process_print (void)
{
/* output times in selected format */
print_time (blocks * hop_size);
outmsg ("t");
/* output extracted mfcc */
fvec_print (mfcc_out);
}
int main(int argc, char **argv) {
int ret = 0;
// change some default params
buffer_size  = 2048;
hop_size = 512;
examples_common_init(argc,argv);
verbmsg ("using source: %s at %dHzn", source_uri, samplerate);
verbmsg ("buffer_size: %d, ", buffer_size);
verbmsg ("hop_size: %dn", hop_size);
pv = new_aubio_pvoc (buffer_size, hop_size);
fftgrain = new_cvec (buffer_size);
mfcc = new_aubio_mfcc(buffer_size, n_filters, n_coefs, samplerate);
mfcc_out = new_fvec(n_coefs);
if (pv == NULL || fftgrain == NULL || mfcc == NULL || mfcc_out == NULL) {
ret = 1;
goto beach;
}
examples_common_process(process_block, process_print);
printf("nlen=%un", mfcc_out->length);
del_aubio_pvoc (pv);
del_cvec (fftgrain);
del_aubio_mfcc(mfcc);
del_fvec(mfcc_out);
beach:
examples_common_del();
return ret;
}

请帮助获得Librosa的相同结果，或建议任何C++库做好这件事。感谢

Answer 1

这可能就是您想要的：C语音功能该库是python_speech_features到C的完整端口，根据文档，您应该能够在C++项目中使用它。Librosa的结果不会一样，原因如下，但你应该能够与他们合作。