我们有一个消息应用程序,旨在显示通知,当它收到消息时,手机被锁定从远程用户,并让本地用户从锁屏输入文本,并发送消息。我该如何实现呢?UNUserNotificationCenter在iOS 10中是可行的吗?
谢谢。
互联网上缺乏结构良好的信息,尽管这是一个非常好的功能,在严肃的信使应用程序中实现。
您应该从UNNotificationContentExtension
开始显示接收到的推送通知的自定义UI。在互联网上选择任何可用的示例,并按照您的意愿实现它。注意bundle ID -它应该是com.yourapp.yourextension
。完成后,你将在Xcode中拥有主应用程序和扩展小部件。
在主应用程序中以iOS10的方式设置推送通知注册:
UNUserNotificationCenter.current().requestAuthorization(options: [.alert, .sound, .badge]) {
(granted, error) in
guard granted else { return }
let replyAction = UNTextInputNotificationAction(identifier: "ReplyAction", title: "Reply", options: [])
let openAppAction = UNNotificationAction(identifier: "OpenAppAction", title: "Open app", options: [.foreground])
let quickReplyCategory = UNNotificationCategory(identifier: "QuickReply", actions: [replyAction, openAppAction], intentIdentifiers: [], options: [])
UNUserNotificationCenter.current().setNotificationCategories([quickReplyCategory])
UNUserNotificationCenter.current().getNotificationSettings { (settings) in
guard settings.authorizationStatus == .authorized else { return }
UIApplication.shared.registerForRemoteNotifications()
}
}
所有的魔法发生在UNTextInputNotificationAction
自定义动作,你添加到你的推送通知处理程序。
要完成设置推送通知,请在扩展名 Info.plist
: NSExtension -> NSExtensionAttributes -> UNNotificationExtensionCategory: "QuickReply"
这都是关于设置。要尝试它,使用Pusher
工具并以这种方式配置推送通知:
{
"aps": {
"alert":"Trigger quick reply",
"category":"QuickReply"
}
}
至少你必须在你的小部件中捕获通知。它发生在控件类的func didReceive(_ notification: UNNotification)
中:
func didReceive(_ notification: UNNotification) {
let message = notification.request.content.body
let userInfo = notification.request.content.userInfo
// populate data from received Push Notification in your widget UI...
}
如果用户响应收到的推送通知,您的小部件将触发以下回调:
func didReceive(_ response: UNNotificationResponse, completionHandler completion: @escaping (UNNotificationContentExtensionResponseOption) -> Void) {
if response.actionIdentifier == "ReplyAction" {
if let textResponse = response as? UNTextInputNotificationResponse {
// Do whatever you like with user text response...
completion(.doNotDismiss)
return
}
}
completion(.dismiss)
}