我想将以下JSON对象淡化为Java对象(位置类):
{
"city": "TEST",
"country": "TEST",
"latitude": "1",
"longitude": "1",
"name": "TEST",
"postalCode": "362001",
"street": "TEST",
"organization": 3
}
我的Java类是:
public class Location{
@ManyToOne
@ForeignKey(name = "FK_location__organization")
private Organization organization;
@NotNull
@Column(nullable = false)
private String name;
private boolean disabled;
private String street;
private String postalCode;
private String city;
private String country;
private Double latitude;
private Double longitude;
@Override
public String toString()
{
return name;
}
public static List<Location> findAllLocationsOrderedByName()
{
return entityManager().createQuery("SELECT o FROM Location o ORDER BY name ASC", Location.class).getResultList();}}
并且,组织类是:
public class Organization {
String name
}
尝试反序列化时出现以下错误:
flexjson.JsonNumber cannot be cast to java.util.Map
flexjson.factories.BeanObjectFactory.instantiate(BeanObjectFactory.java:17)
flexjson.ObjectBinder.bind(ObjectBinder.java:95)
flexjson.ObjectBinder.bindIntoObject(ObjectBinder.java:149)
flexjson.ObjectBinder.bind(ObjectBinder.java:95)
flexjson.ObjectBinder.bind(ObjectBinder.java:74)
flexjson.JSONDeserializer.deserialize(JSONDeserializer.java:158)
flexjson.factories.ClassLocatorObjectFactory.instantiate(ClassLocatorObjectFactory.java:38)
我使用以下代码(使用 Flex JSON)进行反序列化:
import flexjson.JSONDeserializer;
import flexjson.JSONSerializer;
public static Location Location.fromJsonToLocation(String json) {
System.out.println(json);
return new JSONDeserializer<Location>()
.use(null, Location.class).deserialize(json);
}
看看 JSON 中的组织价值。它是整数值,但在 Java 对象中是组织
您可以使用 ObjectMapper 使用以下代码片段将 json 数据转换为相应的 Object:
ObjectMapper mapper = new ObjectMapper();
Location location= mapper.readValue(jsonData, Location.class);