我有独立的XAML文件,这些文件动态加载到MainWindow中。XAML文件包含动画。加载XAML很简单,但加载XAML后让动画工作的正确方法是什么。这是我的测试代码,如果粘贴到常规WPF窗口,它可以正常工作,但如果动态加载,动画似乎不会启动。我怀疑对TargetName和TargetProperty的引用有问题。
XAML:
<Window
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
Title="Page1" Width="1080" Height="1920">
<Grid x:Name="GridWrapper">
<Viewbox x:Name="ViewboxWrapper">
<Grid x:Name="GridMain" Width="1080" Height="1920" Background="Black">
<Grid.Resources>
<Storyboard x:Key="StoryboardPhotos" Duration="0:0:5">
<DoubleAnimation Storyboard.TargetName="LabelPhoto_01" Storyboard.TargetProperty="Opacity" BeginTime="0:0:0" Duration="0:0:5" To="1.0"></DoubleAnimation>
</Storyboard>
</Grid.Resources>
<Grid.RowDefinitions>
<RowDefinition Height="100*"></RowDefinition>
</Grid.RowDefinitions>
<Grid.ColumnDefinitions>
<ColumnDefinition Width="100*"></ColumnDefinition>
</Grid.ColumnDefinitions>
<Label x:Name="LabelPhoto_01" Grid.Row="0" Grid.Column="0" HorizontalAlignment="Center" VerticalAlignment="Center" Style="{StaticResource StyleLabelPhoto}" Opacity="0">
<Image x:Name="ImagePhoto_01" Source="../../../Content/FPO/1.jpg"></Image>
</Label>
</Grid>
</Viewbox>
</Grid>
</Window>
C#代码:
private void MainWindow_OnLoaded(object sender, RoutedEventArgs e)
{
Window window = null;
using (FileStream fs = new FileStream("Templates/16x9/Portrait/1.xaml", FileMode.Open, FileAccess.Read)) //load xaml file
{
window = (Window)XamlReader.Load(fs);
}
Viewbox wrapper = (Viewbox)window.FindName("ViewboxWrapper");
Grid mainGrid = wrapper.FindName("GridMain") as Grid;
var sb = (Storyboard)mainGrid.FindResource("StoryboardPhotos");
//disconnect grid from the parent window
((Grid)wrapper.Parent).Children.Remove(wrapper);
// attach the grid to the main window
GridParent.Children.Add(wrapper);
sb.Begin();
}
在GridParent.Children.Add(wrapper);
后插入以下代码
sb.Begin(window);
window.Close();
否则,您将得到Namescope错误。