如何在嵌套循环中请求用户输入

Question

我的任务是显示斐波那契数，但同时询问用户他/她希望在给定时间计算多少个数。

他们让我参考书中的一个例子。我以为代码中的几行更改就能解决我的问题，但我很难理解这段代码哪里出了问题。

int main()
{ 
    int NumsToCal = 5;
    cout << "How many numbers would you like to calculate?" << endl;
    cin >> NumsToCal;
    cout << " This program will calculate " << NumsToCal << " Fibonacci Numbers at a time" <<endl;
    int Num1 = 0, Num2 = 1;
    char WantMore = '';
    cout << Num1 << " " << Num2 << " " ;
    do 
    {
        for( int Index = 0; Index < NumsToCal; ++Index)
        {
            cout << Num1 + Num2 << " ";
            int Num2Temp = Num2;
            Num2 = Num1 + Num2;
            Num1 = Num2Temp;
        }
        cout <<  "Do you want more numbers (y/n)? " << endl;
        cin >> WantMore;
    } while (WantMore == 'y');
        cout << "Goodbye!" << endl;
    return 0;
}

Answer 1

Xsami是绝对正确的。你只需要再包括一行，比如：

cin>>NumstoCal;

尽管为了更清晰起见，改变输出内容的方式也不错。

这是我的代码：https://ideone.com/BXREP9

Answer 2

您唯一需要做的就是再次读取NumsToCal，并且必须在cin >> WantMore; 之后执行类似操作

if ( WantMore == 'y' ) 
{
    Num1 = 0;
    Num2 = 1;
    cout << "How many numbers would you like to calculate?" << endl;
    cin >> NumsToCal;
    cout << Num1 << " " << Num2 << " " ;
}

这是我的代码：http://ideone.com/a8um5Z