这是我现在正在进行的一个简单的基于文本的冒险的一部分（强调部分）。出于某种原因，每次我运行这个并在任何一点上说"不"时，它仍然会继续执行并执行"是"的代码。也可以随意建议任何清理此代码的方法。我使用互联网自学，对python非常陌生，所以请不要讨厌：）。
if path1 == "1":
while breakhold3 == 0:
if path1 == "1":
poi1 = raw_input ("There is a strange artificial hole in the ground. It is surrounded by yellow bricks and vines cover them. Would you like to investigate?")
if poi1 == "Yes" or "yes" or "ye" or "Ye" or "Y" or "y":
print("You crouch down to look in the hole. When you look in, you find that it goes so deep all you can see is blackness. There is a large rock next to the hole.")
if item == "1":
poic1 = raw_input ("You get out the rope and attatch it to the rock. You throw it down the hole and it is at least 2 seconds before you hear it hit the bottom. Would you like to descend the rope?")
if poic1 == "Yes" or "yes" or "Ye" or "ye" or "Y" or "y":
print ("You slowly descend down the rope. It takes about a minute before you get to the bottom. It is dark here, and you begin to feel around the room with your hands.")
from random import randrange
numberboy = randrange(7,10)
if numberboy == 7:
print ("You unluckily fall into a pit!")
health -= 1
if health == 0:
print ("You drop to your knees and lie, filled with pain in the pit. You drop to the floor. Your quest is over.")
print ("Your health has fallen to " + str(health) + ". ")
if numberboy in (8,9):
print ("You could have fallen into a pit but you luckily didn't!")
print ("You find a path leading of to another room.")
print ("You walk down the path and find a light illuminating an elvish sword!")
print ("You walk out of an escape path and find youself coming out of a secret entrance at the clearing.")
breakhold3 += 1
break
if poic1 == "No" or "no" or "n" or "N":
print ("You decide not to descend down the rope. You continue down the path ahead.")
breakhold3 += 1
if poi1 == "no" or "No" or "n" or "N":
print ("You decide not to investigate. You continue down the path ahead.")
breakhold3 += 1
print ("Check")
import time
注意：我早些时候突破了3=0。
问题在于这种类型的布尔表达式：
if poi1 == "Yes" or "yes" or "ye" or "Ye" or "Y" or "y":
这就是你想要做的：
if poi1 == "Yes" or poi1 == "yes" or poi1 == "ye" or poi1 == "Ye" or poi1 == "Y" or poi1 == "y":
问题是这些字符串本身的求值结果为True。
更好的解决方案可能是检查poi1是否在"是"值列表中：
if poi1.lower() in ["yes", "ye", "y"]:
更简单，但：
if poi1.lower().startswith("y"):
此外，请记住，在您发布的代码中，有几个地方存在不正确的布尔表达式。
或者，尝试一种特别适合文本冒险的语言：
http://inform7.com
http://tads.org
更多信息，请访问http://www.ifwiki.org