无法将关键字'slug'解析为字段。选项包括：正文、评论、日期、ID、标题

Question

嗨，我在帖子上写评论有问题。

这是我的URL

    from django.conf.urls import url
    from django.views.generic import ListView, DetailView
    from forum.models import Post
    from . import views
    from .views import createPost
    urlpatterns = [
       url(r'^$', ListView.as_view(queryset=Post.objects.all().order_by("-date")[:25], template_name="forum/forum.html")),
       url(r'^(?P<pk>d+)$', DetailView.as_view(model=Post, template_name='forum/post.html')),
       url(r'^createPost/', createPost.as_view(), name='createPost'),
       url(r'^(?P<slug>[-w]+)/comment/$', views.add_comment, name='add_comment')
    ]

这是我的观点

    from django.shortcuts import render, redirect
    from .forms import PostForm
    from django.views.generic import TemplateView
    from .forms import CommentForm
    from django.shortcuts import get_object_or_404
    from .models import Post
    class createPost(TemplateView):
        template_name = 'forum/createPost.html'
        def get(self, request):
            form = PostForm()
            return render(request, self.template_name, {'form': form})
        def post(self, request):
            form = PostForm(request.POST)
            if(form.is_valid()):
                form.save()
                return redirect('/forum')
    def add_comment(request, slug):
        post = get_object_or_404(Post, slug=slug)
        if(request.method == "Post"):
            form = CommentForm(request.Post)
            if(form.is_valid()):
                comment = form.save(commit=False)
                comment.post = post
                comment.save()
                return redirect('/forum/createPost', slug=post.slug)
        else:
            form = CommentForm()
        template = 'forum/addComment.html'
        context = {'form': form}
        return render(request, template, context)

最后是我的模型

    from django.db import models
    class Post(models.Model):
        title = models.CharField(max_length=140)
        body = models.CharField(max_length=500)
        date = models.DateTimeField()
        def __str__(self):
            return self.title
    class Comment(models.Model):
        post = models.ForeignKey(Post, related_name='comments', on_delete=None)
        com_title = models.CharField(max_length=140)
        com_body = models.CharField(max_length=500)
        def __str__(self):
            return self.com_title

我认为问题与我使用TemplateViews有关，当我呼叫帖子时，它可以将SLUG放入模板中。我是Django的新手，我真的会为您提供一些帮助。我也有可能是相关的表单文件，因此，如果您认为是，请让我现在让我添加到问题中。谢谢！

Answer 1

比yasin bahtiyar更细节。

添加到您的Post型号

slug = models.SlugField (
    verbose_name = "Slug",
    allow_unicode = True,
    unique=True)

这将确保slug是唯一的，并且您不会收到2个记录，但是您需要确保slug在保存之前是唯一的。

如果您想根据标题设置slug，请执行以下操作：

slug = models.SlugField (
    verbose_name = "Slug",
    allow_unicode = True,
    unique=True,
    blank = True,
    null = True)

并将保存功能添加到模型：

def save(self, *args, **kwargs):
    if not self.slug: self.slug = slugify(self.title)
    super(Post, self).save(*args, **kwargs)

再次，您需要添加代码以确保其唯一。

Answer 2

什么是slug;在django？

中

class Post(models.Model):
    title = models.CharField(max_length=140)
    body = models.CharField(max_length=500)
    date = models.DateTimeField()
    slug = models.SlugField(max_length=40)

Answer 3

尝试python manage.py migrate，它将迁移到数据库