查找值是否等于或介于二维数组中的值之间

Question

我有一个python脚本，它可以捕获日志数据并将其转换为2D数组。

脚本的下一部分旨在循环遍历.csv文件，评估每行的第一列，并确定该值是否等于或介于2D数组中的值之间。如果是，则将最后一列标记为TRUE。如果没有，请将其标记为FALSE。

例如，如果我的2d阵列看起来像这样：

[[1542053213, 1542053300], [1542055000, 1542060105]]

我的csv文件如下所示：

1542053220, Foo, Foo, Foo
1542060110, Foo, Foo, Foo

第一行的最后一列应为TRUE(或1(，而第二行的最后一栏应为FALSE(或0(。

我当前的代码如下：

from os.path import expanduser
import re
import csv
import codecs
#Setting variables
#Specifically, set the file path to the reveal log
filepath = expanduser('~/LogAutomation/programlog.txt')
csv_filepath = expanduser('~/LogAutomation/values.csv')
tempStart = ''
tempEnd = ''
print("Starting Script")
#open the log
with open(filepath) as myFile:
    #read the log
    all_logs = myFile.read()
myFile.close()
#Create regular expressions
starting_regex = re.compile(r'[(d+)s+s]s+Startings+Program')
ending_regex = re.compile(r'[(d+)s+s]s+Endings+Program.s+Stopping')
#Create arrays of start and end times
start_times = list(map(int, starting_regex.findall(all_logs)))
end_times = list(map(int, ending_regex.findall(all_logs)))
#Create 2d Array
timeArray = list(map(list, zip(start_times, end_times)))
#Print 2d Array
print(timeArray)
print("Completed timeArray construction")
#prints the csv file
with open(csv_filepath, 'rb') as csvfile:
    reader = csv.reader(codecs.iterdecode(csvfile, 'utf-8'))
    for row in reader:
        currVal = row[0]
            #if currVal is equal to or in one of the units in timeArray, mark last column as true
            #else, mark last column as false
csvfile.close()
print("Script completed")

我已经成功地迭代了我的.csv，并为每一行获取第一列的值，但我不知道如何进行比较。不幸的是，我不熟悉2D数组数据结构中的值之间的检查。此外，我的.csv文件中的列数可能会波动，因此有人知道一种非静态的方法来确定能够写入文件中最后一列的"最后一列"吗？

有人能为我提供一些帮助吗？

Answer 1

您只需要遍历列表列表，并检查值是否在任何间隔中。这里有一个简单的方法：

with open(csv_filepath, 'rb') as csvfile:
    reader = csv.reader(codecs.iterdecode(csvfile, 'utf-8'))
    input_rows = [row for row in reader]
with open(csv_filepath, 'w') as outputfile:
    writer = csv.writer(outputfile)
    for row in input_rows:
        currVal = int(row[0])
        ok = 'FALSE'
        for interval in timeArray:
            if interval[0] <= curVal <= interval[1]:
                ok = 'TRUE'
                break
        writer.writerow(row + [ok])

上面的代码将把结果写在同一个文件中，所以要小心。我还删除了csvfile.close()，因为如果使用with语句，文件将自动关闭。

Answer 2

我会选择更像蟒蛇的东西。

compare = lambda x, y, t: (x <= int(t) <= y)
with open('output.csv', 'w') as outputfile:
    writer = csv.writer(outputfile)
    with open(csv_filepath, 'rb') as csvfile:
        reader = csv.reader(codecs.iterdecode(csvfile, 'utf-8'))
    for row in reader:
        currVal = row[0]
        #if currVal is equal to or in one of the units in timeArray, mark last column as true
        #else, mark last column as false
        match = any(compare(x, y, currVal) for x, y in timeArray)
        write.writerow(row + ['TRUE' if match else 'FALSE'])
    csvfile.close()
outputfile.close()