SQL基于与另一个表的连接更新表

Question

我试图通过将值与另一个表连接来更新表。以下是我目前的查询。

    UPDATE LOGIN  SET LOGIN.DISABLED_IND = 'N', LOGIN.DREASON = 'Test'
        FROM  CONTACT
        WHERE CONTACT.CONTACT_ID = LOGIN.CONTACT_ID 
        AND CONTACT.RID ='abc'

当我运行这个，我得到这个

[Error Code: 933, SQL State: 42000] ORA-00933: SQL command not properly ended

谢谢

Answer 1

如果您希望更新LOGIN中的大部分行，那么使用EXISTS

可能会更有效。

UPDATE LOGIN  l
   SET l.DISABLED_IND = 'N', 
       l.DREASON = 'Test'
 WHERE EXISTS (
    SELECT 1
      FROM CONTACT c
     WHERE c.CONTACT_ID = l.CONTACT_ID 
       AND c.RID ='abc' )

如果您在LOGIN中更新相对较少的行，那么Yahia使用in的方法可能会更有效

UPDATE LOGIN  l
   SET l.DISABLED_IND = 'N', 
       l.DREASON = 'Test'
 WHERE l.contact_id IN (
    SELECT c.contact_id
      FROM CONTACT c
     WHERE c.RID ='abc' )

Answer 2

try

 UPDATE LOGIN L SET L.DISABLED_IND = 'N', L.DREASON = 'Test'
 WHERE L.CONTACT_ID 
 IN ( SELECT C.CONTACT_ID FROM CONTACT C WHERE C.CONTACT_ID = L.CONTACT_ID AND 
 C.RID='abc');

另一个更复杂的选项见http://geekswithblogs.net/WillSmith/archive/2008/06/18/oracle-update-with-join-again.aspx

Answer 3

您的语法不太正确。这篇维基百科文章有很多例子供您选择。

例如

UPDATE l
 SET l.DISABLED_IND = 'N', l.DREASON = 'Test'
 FROM LOGIN l
  JOIN CONTACT c
   ON c.CONTACT_ID = l.CONTACT_ID AND c.RID ='abc'