Contextmenu StaysOpen属性根本不起作用

Question

我有一个非常奇怪的问题与上下文菜单。考虑下面的简单代码:

<StackPanel>
    <StackPanel.ContextMenu>
        <ContextMenu x:Name="CMenu" StaysOpen="True" >
            <MenuItem Header="Item 1" />
            <MenuItem Header="Item 2">
                <MenuItem Header="Sub item 1" />
                <MenuItem Header="Sub item 2" />
                <MenuItem Header="Sub item 3" />
                <MenuItem Header="Sub item 4" />
            </MenuItem>
            <MenuItem Header="Item 3" />
            <MenuItem Header="Item 4" />
        </ContextMenu>
    </StackPanel.ContextMenu>
    <Label Content="ContextMenu Test" />
    <Button Content="ClickMe" Click="Button_Click" />
</StackPanel>

我设置staysopen为true，然而，只要我点击上下文菜单之外的任何地方，它就会关闭。这个属性是用来干什么的?如何防止上下文菜单关闭?(点击clickme按钮跟踪StaysOpen状态，它总是为真)

Answer 1

要保持菜单打开，即使在点击后，你必须设置下面的属性为true为每个菜单项

StaysOpenOnClick="True"

所以根据您的要求，您的代码将如下所示:

<StackPanel>
        <StackPanel.ContextMenu>
            <ContextMenu x:Name="CMenu" StaysOpen="True" >
                                       <MenuItem Header="Item 1" StaysOpenOnClick="True"/>
                    <MenuItem Header="Item 2" StaysOpenOnClick="True">
                        <MenuItem Header="Sub item 1" StaysOpenOnClick="True"/>
                        <MenuItem Header="Sub item 2" StaysOpenOnClick="True"/>
                        <MenuItem Header="Sub item 3" StaysOpenOnClick="True"/>
                        <MenuItem Header="Sub item 4" StaysOpenOnClick="True"/>
                    </MenuItem>
                    <MenuItem Header="Item 3" StaysOpenOnClick="True"/>
                    <MenuItem Header="Item 4" StaysOpenOnClick="True"/>
            </ContextMenu>
        </StackPanel.ContextMenu>
        <Label Content="ContextMenu Test" />
        <Button Content="ClickMe" Click="Button_Click" />
    </StackPanel>

Answer 2

我想你应该用Popup代替:

 <StackPanel>
        <Popup IsOpen="True"
               StaysOpen="True"
               PlacementTarget="{Binding RelativeSource={RelativeSource FindAncestor,AncestorType={x:Type Panel}}}">
            <ListBox>
                <ListBoxItem Content="1" />
                <ListBoxItem Content="2" />
            </ListBox>
        </Popup>
        <Label Content="ContextMenu Test" />
        <Button Content="ClickMe" />
    </StackPanel>

然而，你应该根据你的窗口的移动来注意这个弹出框的位置。意味着重新定义它的X和y