Rails Acts_as_votable与Ajax的Gem Like/不同点按钮



我是Ruby On Rails的新手,我使用acts_as_votable gem来创建喜欢和不喜欢的按钮,让用户喜欢和不喜欢的帖子,但我不能让他们从喜欢到不喜欢(反之亦然),并且每次点击时更新计数器而不刷新页面。我试着遵循其他类似的答案,但我没有运气。如果没有我试图实现Ajax所做的混乱的更改,我的代码看起来像这样:

Post Model acts_as_votable和User Model acts_as voter

Posts Controller has

def like
  @post = Post.find(params[:id])
  @post.liked_by current_user
  redirect_to :back
end
def unlike
  @post = Post.find(params[:id])
  @post.unliked_by current_user
  redirect_to :back
end

航线

resources :posts do
  member do
    put 'like', to: "posts#like"
    put 'unlike', to: "posts#unlike"
  end
end

视图

<%= @post.get_likes.size%>
  <% if @post.get_likes.size ==1 %>
    person like this
  <% else %>
   people like this
<% end %>

<div class="btn-group">
  <% if (current_user.liked? @post) %>
    <%= link_to unlike_post_path(@post), method: :put, class: "btn btn-default btn-sm" do %>
    <span class="glyphicon glyphicon-chevron-down"></span>
      Unlike
    <%end %>
  <% else %>
    <%= link_to like_post_path(@post), method: :put, class: "btn btn-primary btn-sm" do %>
    <span class="glyphicon glyphicon-chevron-up"></span>
      Like
    <% end %>
  <% end %>
</div>

我读了很多关于Ajax的答案,但我无法复制结果。提前感谢!

首先,您需要指出您的posts控制器来响应js格式。那么posts_controller中的两个动作变成:

def like
  @post = Post.find(params[:id])
  @post.liked_by current_user
  respond_to do |format|
    format.html { redirect_to :back }
    format.js { render layout: false }
  end
end
def unlike
  @post = Post.find(params[:id])
  @post.unliked_by current_user
  respond_to do |format|
    format.html { redirect_to :back }
    format.js { render layout: false }
  end
end

第二,你需要在你的链接上传递remote: true:

 <div class="votes">
    <% if current_user.liked? @post %>
       <%= link_to unlike_post_path(@post), method: :get, remote: true, class: 'unlike_post' %>
     <% else %>
       <%= link_to like_post_path(@post), method: :get, remote: true, class: 'like_post' %>
     <% end %>
  </div>

我将method: :put更改为method: :get,因此在config/routes.rb中更改它,并添加到您的链接中绑定它。

最后,您需要在app/views/posts/中创建2个视图:
  • like.js.erb

    $('.like_post').bind('ajax:success', function(){
       $(this).parent().parent().find('.vote_count').html('<%= escape_javascript @post.votes_for.size.to_s %>');
       $(this).closest('.like_post').hide();
       $(this).closest('.votes').html(' <%= link_to "Unlike", unlike_post_path(@post), remote: true, method: :get, class: 'unlike_post' %>');
    });
    
  • unlike.js.erb

    $('.unlike_post').bind('ajax:success', function(){
       $(this).parent().parent().find('.vote_count').html('<%= escape_javascript @post.votes_for.size.to_s %>');
       $(this).closest('.unlike_post').hide();
       $(this).closest('.votes').html(' <%= link_to "Like", like_post_path(@post), remote: true, method: :get, class: 'like_post' %>');
    });
    

处理计数的更新,我使用.vote_count类,所以在您的视图:

<div class="vote_count">
  <%= @post.get_likes.size %>
</div> 

所以我的观点是:

<div>
  <div class="vote_count">
    <%= @post.get_likes.size %>
  </div> 
  <div class="votes">
    <% if current_user.liked? @post %>
      <%= link_to unlike_post_path(@post), method: :get, remote: true, class: 'unlike_post' %>
    <% else %>
      <%= link_to like_post_path(@post), method: :get, remote: true, class: 'like_post' %>
    <% end %>
  </div>
</div>

编辑:我编辑我的答案。用class代替id更新链接。并看看2js视图找到最接近()。在我的沙箱应用中,它在indexshow页面中工作得很好。所以请随意调整您的标记

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