以下是用于查找特定列计数的python map-reduce脚本。输入文件如下:
301838690844557314|#awkwarddate first date at quiznoes|334910568|gabriellarichh|20130213|awkwarddate|Point|40.456664|-74.265167
301838679280861185|RT @jimmyfallon: Ended my very first date by saying, "Take it easy." And then my dad drove me home. #awkwarddate|618516844|heyitsbrooke456|20130213|awkwarddate|NULL|NULL|NULL
301838678026768384|RT @jimmyfallon: Hashtag game! Tweet out a funny, weird, or embarrassing story about a date you've been on and tag w/ #awkwarddate. Could be on our show!|116973704|VegasPhotog|20130213|awkwarddate|NULL|NULL|NULL
map reduce脚本如下:映射代码为:
import sys
def read_input(file):
for line in file:
# split the line into words
yield line.split('|')
def main(separator='|'):
# input comes from STDIN (standard input)
data = read_input(sys.stdin)
for words in data:
# write the results to STDOUT (standard output);
# what we output here will be the input for the
# Reduce step, i.e. the input for reducer.py
#
# tab-delimited; the trivial word count is 1
if len(words)==9:
for word[5] in words:
print '%s%s%d' % (word[5], separator, 1)
if __name__ == "__main__":
main()
reduce code:
from itertools import groupby
from operator import itemgetter
import sys
def read_mapper_output(file, separator='|'):
for line in file:
yield line.rstrip().split(separator, 1)
def main(separator='|'):
# input comes from STDIN (standard input)
data = read_mapper_output(sys.stdin, separator=separator)
# groupby groups multiple word-count pairs by word,
# and creates an iterator that returns consecutive keys and their group:
# current_word - string containing a word (the key)
# group - iterator yielding all ["<current_word>", "<count>"] items
for current_word, group in groupby(data, itemgetter(0)):
try:
total_count = sum(int(count) for current_word, count in group)
print "%s%s%d" % (current_word, separator, total_count)
except ValueError:
# count was not a number, so silently discard this item
pass
if __name__ == "__main__":
main()
当我在hadoop中运行上述脚本时,我得到以下错误:
failed Map Tasks exceeded allowed limit. FailedCount: 1. LastFailedTask: task_201302281754_0001_m_000000
我想要得到第6列(awkwarddate)的计数任何帮助都会很感激。提前感谢
让我们进一步细分一下,因为您想计算每行的第6列。
def to_std_out(line, sep='|'):
words = line.split(sep)
print '%s%s%d' % (words[5], sep, 1)
现在在脚本入口点(在您的示例中表示为main()
函数)中,逻辑可以是:
def main(sep='|'):
# read in stdin line by line, usually you might need an indefinite loop
# for the sake of simplicity, I'll be using while 1
while 1:
lines = sys.stdin.readlines()
for line in lines:
to_std_out(line, sep)
希望这是你正在寻找的:)