am正在开发一个应用程序,该应用程序可以将图像以及用户的名字和第二个名字发送到服务器。应用程序可以将图像发送到服务器,但我无法检索用户的名字和第二个名字。下面是我的代码
java
HttpClient httpClient = new DefaultHttpClient();
HttpContext localContext = new BasicHttpContext();
HttpPost httpPost = new HttpPost(
"http://192.168.1.144/app_api/samplerEG.php");
MultipartEntity entity = new MultipartEntity(
HttpMultipartMode.BROWSER_COMPATIBLE);
ByteArrayOutputStream bos = new ByteArrayOutputStream();
bitmap.compress(CompressFormat.JPEG, 100, bos);
byte[] data = bos.toByteArray();
entity.addPart("fname", new StringBody(user_fname));
entity.addPart("lname", new StringBody(user_lname));
entity.addPart("file", new ByteArrayBody(data, "picture.jpg"));
httpPost.setEntity(entity);
HttpResponse response = httpClient.execute(httpPost,
localContext);
BufferedReader reader = new BufferedReader(
new InputStreamReader(
response.getEntity().getContent(), "UTF-8"));
String sResponse = reader.readLine();
return sResponse;
php是
$fname = $_POST["fname"];
$lname = $_POST["lname"];
$date_of_birth = $_POST["dob"];
$pnumber = $_POST["pnumber"];
$district_name = $_POST["district_name"];
$gender = basename($_POST['gender']);
$picture = md5(basename($_FILES['file']['name'])).".jpg";
我哪里可能出错
FileBody uploadVideo = new FileBody(new File(filePath));
MultipartEntity reqEntity = new MultipartEntity();
reqEntity.addPart( "file", uploadVideo );
try {
reqEntity.addPart( "ToId", new StringBody(contactId));
reqEntity.addPart( "type", new StringBody("1"));
reqEntity.addPart( "MsgText", new StringBody(""));
reqEntity.addPart( "FromId", new StringBody(pref.getUserId()));
reqEntity.addPart( "UniqueId", new StringBody(ControllerActivity.DEVICE_UNIQUE_ID));
} catch (UnsupportedEncodingException e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
}
您只需要使用FileBody而不是