我有一个TcpListener，它得到了无穷无尽的byte array。由此，我将byte((转换为MemoryStream，并输入一个PictureBox来显示图像。这工作正常。 如果我将 PictureBox 上的锚点设置为top/right/bottom/left这意味着图像将在表单展开时展开，然后我实际展开表单，则会出现以下错误：
An unhandled exception of type 'System.ArgumentException' occurred in System.Drawing.dll
Additional information: Parameter is not valid.
也
The application is in break mode
法典
' Enter the listening loop.
While True
Dim client As TcpClient = Await server.AcceptTcpClientAsync()
Dim stream As NetworkStream = client.GetStream
Dim MS As New MemoryStream
Await stream.CopyToAsync(MS)
Await ViewImage(MS)
client.Close()
End While
查看图像功能：
Public Async Function ViewImage(ms As MemoryStream) As Task
Try
Dim myimage As Bitmap
myimage = New Bitmap(ms)
PictureBox1.Image = myimage
PictureBox1.Refresh()
myimage.Dispose()
Catch ex As Exception
MessageBox.Show(ex.ToString)
End Try
End Function
请注意，我的代码中没有捕获异常。有什么想法吗？
此问题很可能与您在ViewImage()方法结束时释放myimage有关。
这：
PictureBox1.Image = myimage
...
myimage.Dispose()
使myimage和PictureBox1.Image指向同一个Bitmap对象。位图是引用类型(类(，这意味着当您将其分配给不同的变量时，您只是传递它们的引用指针。
因此，当您处置myimage时，您正在处置PictureBox中显示的相同图像，当GDI+尝试重绘它的拉伸版本时，这可能会导致您的错误(事实上，一旦您处置了原始图像，甚至不应该显示原始图像(。
有关详细信息，请参阅：值类型和引用类型 - Microsoft文档。
引用类型和值类型如何工作的基本示例
参考类型：
Dim A As New Bitmap("image.bmp")
Dim B As Bitmap = A 'Points to A.
PictureBox1.Image = A 'Points to A.
PictureBox2.Image = B 'Still points to A.
'Calling Dispose() on any of the above will result in none of them having an image since you will ultimately dispose bitmap A.
值类型：
Dim A As Integer = 3
Dim B As Integer = A 'Copy of A.
Dim C As Integer = B 'Copy of B.
C = 4 'Results in A = 3, B = 3, C = 4.