如何用列表分隔文本?

Question

这是我的代码，但是当我希望它计算句子中的字符数时，它会一直将答案输出为一个。

#-----------------------------
myList = []
characterCount = 0
#-----------------------------
Sentence = "hello world"
newSentence = Sentence.split(",")
myList.append(newSentence)
print(myList)
for character in myList:
characterCount += 1
print (characterCount)

谢谢你的帮助

Answer 1

单行解决方案

len(list("hello world"))  # output 11

或。。。

快速修复原始代码

修订后的代码：

#-----------------------------
myList = []
characterCount = 0
#-----------------------------
Sentence = "hello world"
myList = list(Sentence)
print(myList)
for character in myList:
characterCount += 1
print (characterCount)

输出：

['h', 'e', 'l', 'l', 'o', ' ', 'w', 'o', 'r', 'l', 'd']
11

Answer 2

您可以遍历句子并按以下方式计算字符数：

#-----------------------------
myList = []
characterCount = 0
#-----------------------------
Sentence = "hello world"
for character in Sentence:
characterCount += 1
print(characterCount)

Answer 3

基本上你犯了一些错误：拆分分隔符应该是''而不是'，'，不需要创建一个新列表，而且你循环使用单词而不是字符。

代码应如下所示：

myList = []
characterCount = 0
#-----------------------------
Sentence = "hello world"
newSentence = Sentence.split(" ")
for words in newSentence:
characterCount += len(words)
print (characterCount)