是否有一种优雅的方式将可变名称中的单个单词提取到数组中

Question

基本上我想这样做：

我得到了一个字符串"myVariableName"并将其变成：["my", "variable", "name"]

我尝试使用Regex进行此操作，但是看来我的结尾阵列中得到了很多不确定的。在这种情况下，可变名称的两种可能情况是骆驼案和上蛇案例。

const matchVariableNames =  /(b[a-z]+)|([A-Z][a-z]+)|(b[A-Z]+)|(_[A-Z]+)/g;
const variableName = 'myVariable';
let words = [];
let regexMatches;
while (regexMatches = matchVariableNames.exec(variableName)) {
  regexMatches.forEach((match) => {
    words.push(match);
  }); 
};

输出：

["my", "my", undefined, undefined, undefined, "Variable", undefined, "Variable", undefined, undefined]
undefined

Answer 1

您可以使用带有大写字母的正面lookahead。然后仅映射较低的案例字母。

var string = 'myVariableName',
    array = string.split(/(?=[A-Z])/).map(a => a.toLowerCase());
    
console.log(array);

Answer 2

我认为正则表达式不适合此。(我不接受正则表达式以识别带有大写字母的骆驼句单词，因为该问题不要求正则表达式persé(。

我阅读的方式是您要解析用骆驼写的单词。我立即想象特殊情况，例如"DOMElement和"PDFParser"。我希望输出为[ "DOM", "Element" ]和[ "PDF", "Parser" ]。我认为我们可以编写这样的函数。

function parseWordsFromCamelCaseString(string) {
  var i, words, last_word_char, last_case, current_case;
  words = [];
  last_word_start = 0;
  last_case = null; // false=lower, true=upper
  for (i = 0; i < string.length; i += 1) {
    current_case = string[i].toUpperCase() === string[i];
    if (last_case !== null && current_case !== last_case) {
      if (current_case === true) { // lowercase to uppercase transition
        words.push(string.substring(last_word_start, i));
        last_word_start = i;
      } else { // uppercase to lowercase transition
        if (last_word_start < i - 1) {
          words.push(string.substring(last_word_start, i - 1));
        }
        last_word_start = i - 1;
      }
    }
    last_case = current_case;
  }
  if (last_word_start < i - 1) {
    words.push(string.substring(last_word_start, i));
  }
  return words;
}
console.log(parseWordsFromCamelCaseString("fooBar"));
console.log(parseWordsFromCamelCaseString("parseWordsFromCamelCaseString"));
console.log(parseWordsFromCamelCaseString("DOMElement"));
console.log(parseWordsFromCamelCaseString("fooDOMElement"));

输出

["foo", "Bar"]
["parse", "Words", "From", "Camel", "Case", "String"]
["DOM", "Element"]
["foo", "DOM", "Element"]

它也适用于"foo"(无案例过渡(和""(空字符串(。

Answer 3

我已经创建了这个：

x = 'myVariableName';
const isUpper = e => (e === e.toUpperCase());
[].reduce.call(x, (words, letter, i) => {
  if(isUpper(letter)) words.push([letter]);
  else {
    let length = words.length-1,
        word = words[length];
    words[length] = word+letter;
  }
  return words;
}, [[]]);

返回["my", "Variable", "Name"]

它非常优雅吗？我们可以为此而战，但我敢肯定，比您的言论更多。：p