Node.js 'q'包异步同步

Question

我正在使用q包将我的js代码从异步转换为同步。 我不知道我的理解是否正确。 我已经写了下面的片段

var Q = require('q')
function onMessage() {
console.log("Before calling Q.fncall");
Q.fcall(processMessage)
.then(function () {
console.log("processMessage execution compleated");
})
.done();
console.log("Calling Q.fncall Compleated");
return true;
}
function processMessage() {
var defer = Q.defer();
console.log("processMessage Entered");
setTimeout(function () {
console.log("processMessage processed");
defer.resolve();
console.log("processMessage defer Resolved");
}, 10)
console.log("ProcessMessage Before Exit");
return defer.promise;
}
onMessage()

代码的输出为 ：：：： Before calling Q.fncall Calling Q.fncall Compleated processMessage Entered ProcessMessage Before Exit processMessage processed processMessage defer Resolved processMessage execution compleated

但我的期望是得到 ：：：： Before calling Q.fncall processMessage Entered ProcessMessage Before Exit processMessage processed processMessage defer Resolved processMessage execution compleated Calling Q.fncall Compleated

我错过了什么，或者如何实现这一点......

Answer 1

这应该可以解决

var Q = require('q')
function onMessage() {
console.log("Before calling Q.fncall");
return new Promise(resolve => {
Q.fcall(processMessage)
.then(function () {
console.log("processMessage execution compleated");
console.log("Calling Q.fncall Compleated");
})
.done(() => resolve(true));
})
}
function processMessage() {
var defer = Q.defer();
console.log("processMessage Entered");
setTimeout(function () {
console.log("processMessage processed");
defer.resolve();
console.log("processMessage defer Resolved");
}, 10)
console.log("ProcessMessage Before Exit");
return defer.promise;
}
onMessage();