我正在尝试获取有关Spesific演员的所有详细信息,并且要找到这个Spesific Actors,我拥有的功能可以回收XMLDOC和2个字符串参数:名字和姓氏,以及在我的代码中在下面,我总是得到0个nodeeslements。有人可以告诉我我做错了什么吗?
public XmlNodeList Query3(XmlDocument xmlDoc, String actorFirstName, String actorLastName)// returns all the awards of all TV-shows of an actor
{
string s = "Netflix/movies/movie/actors/actor[first-name="+actorFirstName+"last-name="+actorLastName+"]";
XmlNodeList xmlNodeList = xmlDoc.SelectNodes(s);
foreach (XmlNode x1 in xmlNodeList)
{
Console.WriteLine(x1.InnerText);
}
return xmlNodeList;
}
xmldoc:
<?xml version="1.0"?>
<Netflix>
<movies>
<movie>
<name>Mister Glass</name>
<genre>Drama</genre>
<year>2019</year>
<actors>
<actor>
<first-name>James</first-name>
<last-name>McAvoy</last-name>
<year-of-birth>1979 </year-of-birth>
<awards>
<award>
<category>Alliance of Women Film Journalists</category>
<year>2007</year>
</award>
<award>
<category>ALOS Awards</category>
<year>2018</year>
</award>
</awards>
</actor>
<actor>
<first-name>Bruce</first-name>
<last-name>Willis</last-name>
<year-of-birth>1955 </year-of-birth>
<awards>
<award>
<category>American gun rights advocates</category>
<year>2007</year>
</award>
<award>
<category>American film producers</category>
<year>2013</year>
</award>
<award>
<category>American male video game actors</category>
<year>2012</year>
</award>
<award>
.
.
.
.
更改
[first-name="+actorFirstName+"last-name="+actorLastName+"]";
to
[first-name="+actorFirstName+" and last-name="+actorLastName+"]";
^^^^^