我有以下代码。当我编写数组"地址"时,我收到"分段错误内存转储"的错误。人'的任何值。任何人请帮我解决问题。
#include <stdio.h>
typedef struct
{
char Person[15];
} stName;
typedef struct
{
stName Name;
} stSociety;
stSociety* SOCIETY;
#define ADDRESS SOCIETY->Name
int main()
{
int i;
for (i=0; i<32; i++)
{
ADDRESS.Person[i] = 0;
}
printf("ADDRESS.Person=%sn", ADDRESS.Person);
printf("Finished");
return 0;
}
你刚刚声明了结构,你也需要创建它们,因此,社会什么都没有指向。此外,您正在迭代 32 个值,而 char 数组中只有 15 个值。我已经修改了代码,希望你能在这里得到一个想法
#include <stdio.h>
typedef struct
{
char Person[15];
} stName;
typedef struct
{
stName Name;
} stSociety;
#define ADDRESS SOCIETY->Name
int main()
{
stSociety* SOCIETY,sample;
SOCIETY = &sample;
int i;
for (i=0; i<15; i++)
{
ADDRESS.Person[i] = '0';
}
printf("ADDRESS.Person=%sn", ADDRESS.Person);
printf("Finished");
return 0;
}