我有以下测试:
testHarness.processElement2(new StreamRecord<>(element1));
testHarness.processElement1(new StreamRecord<>(new Tuple2<>(id, element2)));
testHarness.setProcessingTime(1); //let's assume it's the correct time for the timer inside the function
softly.assertThat(testHarness.getOutput()).containsExactly(new StreamRecord<>(expectedResult)); //this one is passed
testHarness.setProcessingTime(2); // setting second timer which will trigger different timer
softly.assertThat(testHarness.getOutput()).containsExactly(new StreamRecord<>(expectedResult2)); //fails cause output has expectedResult & expectedResult2
为什么一旦我们调用getOutput((,TestHarness就不清除它的元素?这个功能能以某种方式实现吗?
这可以通过对输出调用clear((来实现:
testHarness.processElement2(new StreamRecord<>(element1));
testHarness.processElement1(new StreamRecord<>(new Tuple2<>(id, element2)));
testHarness.setProcessingTime(1); //let's assume it's the correct time for the timer inside the function
softly.assertThat(testHarness.getOutput()).containsExactly(new StreamRecord<>(expectedResult)); // Pass
testHarness.getOutput().clear();
testHarness.setProcessingTime(2); // setting second timer which will trigger different timer
softly.assertThat(testHarness.getOutput()).containsExactly(new StreamRecord<>(expectedResult2)); // Pass