竞争性编程:如何检查 python 列表中是否存在变量的值?

Question

以下问题是在我的一个能力倾向测试中提出的。我尝试使用python解决。问题如下：

COVID19 Patients are with identity numbers from 1 to 10. 
But few patients are escaped from quarantine. 
Find out those patients and write their names and details.
Below are details of patients.
1 Raju 
2 Ravi 
3 Lakshmi 
4 Yash 
5 Renu 
6 Tanvi 
7 Usha 
8 Vicky 
9 Rocky
10 Manu

输出和输入的格式如下：

Input Format
Line 1: String
Line 2: String 
Line 3: String 
Line 4: String 
Line 5: String 
Line 6: String 
Line 7: String 
Line 8: String
Line 9: String

Constraints
None
Output Format
Line 1: String

示例输入和输出如下：

Sample Input 0
Raju
Ravi 
Lakshmi
Yash
Tanvi
Usha
Vicky
Rocky 
Manu
Sample Output 0
Renu

因此，我将所有名称都提供给一个名为 Patient[] 的数组。我的问题程序如下：

patient=[
"Raju",
"Ravi",
"Lakshmi",
"Yash",
"Renu",
"Tanvi",
"Usha",
"Vicky",
"Rocky",
"Manu"
]
for i in range(0,):
item=input()
if item not in patient:
print(item)

Answer 1

您不能迭代range(0,)，因为没有定义终点，它必须range(0,len(patient))

那么这就是你的循环的样子：

for i in range(0,len(patient)):
item=input()
if item not in patient:
print(item)