我希望输出类似于 [[1,2,3,4,5,6,7,8,9,10]，[2,4,6,8,10,12..18,20]，[3,6

Question

我正在使用python。我需要获得输出，正如我在底部提到的。这就是我尝试的方式。

L = [i for i in range(1,11)]
print(L)
p = []
p.extend(L for _ in range(10))
#print(p)
for _ in range(10):
for i in range(10):
p[_][i] = (_+1)*p[_][i]
print(p)
and this is the output I got.

输出：[[3628800， 7257600， 10886400， 14515200， 18144000， 21772800 25401600, 29030400, 32659200, 36288000], [3628800, 7257600, 10886400, 14515200, 18144000, 21772800, 25401600, 29030400, 32659200, 36288000], [3628800, 7257600, 10886400, 14515200, 18144000, 21772800, 25401600, 29030400, 32659200, 36288000], [3628800, 7257600, 10886400, 14515200, 18144000, 21772800, 25401600, 29030400, 32659200, 36288000], [3628800, 7257600, 10886400, 14515200, 18144000, 21772800, 25401600, 29030400, 32659200, 36288000], [3628800, 7257600, 10886400, 14515200, 18144000, 21772800, 25401600, 29030400, 32659200, 36288000], [3628800, 7257600, 10886400, 14515200, 18144000, 21772800, 25401600, 29030400, 32659200, 36288000], [3628800, 7257600, 10886400, 14515200, 18144000, 21772800, 25401600, 29030400, 32659200, 36288000], [3628800, 7257600, 10886400, 14515200, 18144000, 21772800, 25401600, 29030400, 32659200, 36288000], [3628800, 7257600, 10886400, 14515200, 18144000, 21772800, 25401600, 29030400， 32659200， 36288000]]

我希望输出是这样的

[[1,2,3,4,5,6,7,8,9,10],[2,4,6,8,10,12...18,20],[3,6,9...27,30].....[9,18,27..90]]

Answer 1

有几个问题： 不要使用 _ 作为变量名称，它用于您不会重用的变量。

由于以下行，您会遇到此问题：

p.extend(L for _ in range(10))

p 是对 L 的引用列表。因此，当您这样做时：

p[_][i] = (_+1)*p[_][i]

您修改 L，从而修改 p 中的所有列表。

您的代码已修复：

p = []
p.extend(list(range(1,11)) for _ in range(10))
for i in range(10):
for j in range(10):
p[i][j] = (i+1)*p[i][j]
print(p)

但是，有一种更简单的方法可以做到这一点：

p  = [ list(range(i, i*11, i )) for i in range(1,10)]

Answer 2

L = [i for i in range(1,11)]
print(L)
d = []
for i in range(1, 11):
d.append([i * j for j in L])
print(d)

输出：

[[1, 2, 3, 4, 5, 6, 7, 8, 9, 10], [2, 4, 6, 8, 10, 12, 14, 16, 18, 20], [3, 6, 9, 12, 15, 18, 21, 24, 27, 30], [4, 8, 12, 16, 20, 24, 28, 32, 36, 40], [5, 10, 15, 20, 25, 30, 35, 40, 45, 50], [6, 12, 18, 24, 30, 36, 42, 48, 54, 60], [7, 14, 21, 28, 35, 42, 49, 56, 63, 70], [8, 16, 24, 32, 40, 48, 56, 64, 72, 80], [9, 18, 27, 36, 45, 54, 63, 72, 81, 90], [10, 20, 30, 40, 50, 60, 70, 80, 90, 100]]

Answer 3

您可以使用列表推导：

new_data = [list(filter(lambda x:not x%i, range(i, (10*i)+1))) for i in range(1,10)]

输出：

[[1, 2, 3, 4, 5, 6, 7, 8, 9, 10], [2, 4, 6, 8, 10, 12, 14, 16, 18, 20], [3, 6, 9, 12, 15, 18, 21, 24, 27, 30], [4, 8, 12, 16, 20, 24, 28, 32, 36, 40], [5, 10, 15, 20, 25, 30, 35, 40, 45, 50], [6, 12, 18, 24, 30, 36, 42, 48, 54, 60], [7, 14, 21, 28, 35, 42, 49, 56, 63, 70], [8, 16, 24, 32, 40, 48, 56, 64, 72, 80], [9, 18, 27, 36, 45, 54, 63, 72, 81, 90]]