如何在我的元类中获取类的父类

Question

我有以下脚本：

#!/usr/bin/python3
class MyMeta(type):
    def __new__(mcs, name, bases, dct):
        print(name + " " + str(bases))
        return super(MyMeta, mcs).__new__(mcs, name, bases, dct)

class A(metaclass=MyMeta):
    def foo(self):
        pass

class B(A):
    pass

class C(B):
    def foo(self):
        pass

def main():
    pass

if __name__ == "__main__":
    main()

我得到以下输出：

A ()
B (<class '__main__.A'>,)
C (<class '__main__.B'>,)

但我期待它：

A ()
B (<class '__main__.A'>,)
C (<class '__main__.B'>, <class '__main__.A'>)

我哪里犯了错误？

Answer 1

bases 类定义中列出的参数列表基类。

似乎你想要class.mro：

class MyMeta(type):
    def __new__(mcs, name, bases, dct):
        ret = super(MyMeta, mcs).__new__(mcs, name, bases, dct)
        print(name + " " + str(ret.mro()[1:-1]))
        return ret