Facebook:列出所有带有个人资料图片的朋友,单击重定向到其他链接



我正在使用Facebook查看使用此特定应用程序的所有朋友。分别重定向到他们的Facebook页面。单击时,我想重定向到Facebook页面以外的其他链接。是否可以 ?如何?

我的代码是

<script>
FB.init({
    appId  : '********', //App ID
    channelUrl : 'http://www.***.in/', // Channel File
    status : true, 
    cookie : true,
    xfbml  : true 
});
FB.getLoginStatus(function(response) {
    if (response.session) {
        globaluserid=response.session["uid"];
        //fetching friends uids from 'friend' table. We are using FB.api syntax
        FB.api(
                {
                method: 'fql.query',
                query: 'SELECT uid1 FROM friend WHERE uid2='+globaluserid
                },
                function(response) {
                //once we get the response of above select query we are going to parse them
                for(i=0;i<response.length;i++)
                {
                //fetching name and square profile photo of each friends
                    FB.api(
                    {
                        method: 'fql.query',
                        query: 'SELECT name,pic_square,username FROM user WHERE uid='+response[i].uid1
                    },
                    function(response) {
                        //creating img tag with src from response and title as friend's name
                        htmlcontent='<img src='+response[0].pic_square+' title='+response[0].name+' alt='+response[0].username+' />';

                    }
                    );
                }
            }
        );
        } else {
            // no user session available, someone you dont know
            top.location.href="../kfb_login.php";
        }
    });
</script>
<div class="just_trying">
<div class="fb-login-button" data-show-faces="true" data-width="200" data-max-rows="1">    </div> </div>

在您提供的代码样本中,您的fb.api实际上并没有用它检索到的信息做任何事情。您将其分配给htmlcontent变量,但是您并没有使用此变量将内容注入到任何地方的HTML主体中。您看到的朋友照片列表来自登录按钮标签,data-show-faces="true"表示登录按钮将显示一个由Facebook代码独家生成的脸部。

所以,您要将data-show-faces设置为false并将JavaScript代码修改为:

function(response) {
  //creating img tag with src from response and title as friend's name
  htmlcontent = document.createElement('img');
  htmlcontent.src = response[0].pic_square;
  htmlcontent.title = response[0].name;
  htmlcontent.alt = response[0].username;
  document.getElementsByTagName('body')[0].appendChild(htmlcontent);
}

为简单起见,如果您使用的是jQuery,则将其修改为:

function(response) {
  //creating img tag with src from response and title as friend's name
  htmlcontent = '<img src='+response[0].pic_square+' title='+response[0].name+' alt='+response[0].username+' />'
  $('body').append(htmlcontent);
}

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