将图像编码为base64，获取无效的base64字符串(使用base64encodedStringWithOptions

Question

这是我的代码。

  UIImage *img = [UIImage imageNamed:@"white.jpeg"];
  NSData *imageData = UIImagePNGRepresentation(img);
  NSString *imageString = [imageData base64EncodedStringWithOptions:0];
  NSLog(@"%@", imageString);

我总是得到无效的base64字符串，其中包括空间。

iVBORw0KGgoAAAANSUhEUgAAARMAAAC3CAIAAAC MS2jAAAAHGlET1QAAAACAAAAAAAAAFwAAAAoAAAAXAAAAFsAAAMC oRdmgAAAs5JREFUeAHs1tFKI1EABFH//5NNVh02uA LQhwoCZ0zj5LbTlffInl58yCAwM8JvPz8iBMIIPDGHJcAgTMEmHOGmjMIMMcdQOAMAeacoeYMAsxxBxA4Q4A5Z6g5gwBz3IGHIPD zfMQL/fVSzDnKyr 9usEvhHn/ddf5N5/yJx7SflcSoA5KV7hz0Lgn0gPW9h3zsNO81wvdr1e/3w R3PmPNf82p4mcLlcDnlu/txCbvKcDqwP s6pCcu/i8Bhzn/yMOcucD705ARe/z43eY5fbQcN5jz5lVB/k4Bfa5u7alUTYE5NWP4mAeZs7qpVTYA5NWH5mwSYs7mrVjUB5tSE5W8SYM7mrlrVBJhTE5a/SYA5m7tqVRNgTk1Y/iYB5mzuqlVNgDk1YfmbBJizuatWNQHm1ITlbxJgzuauWtUEmFMTlr9JgDmbu2pVE2BOTVj JgHmbO6qVU2AOTVh ZsEmLO5q1Y1AebUhOVvEmDO5q5a1QSYUxOWv0mAOZu7alUTYE5NWP4mAeZs7qpVTYA5NWH5mwSYs7mrVjUB5tSE5W8SYM7mrlrVBJhTE5a/SYA5m7tqVRNgTk1Y/iYB5mzuqlVNgDk1YfmbBJizuatWNQHm1ITlbxJgzuauWtUEmFMTlr9JgDmbu2pVE2BOTVj JgHmbO6qVU2AOTVh ZsEmLO5q1Y1AebUhOVvEmDO5q5a1QSYUxOWv0mAOZu7alUTYE5NWP4mAeZs7qpVTYA5NWH5mwSYs7mrVjUB5tSE5W8SYM7mrlrVBJhTE5a/SYA5m7tqVRNgTk1Y/iYB5mzuqlVNgDk1YfmbBJizuatWNQHm1ITlbxJgzuauWtUEmFMTlr9JgDmbu2pVE2BOTVj JgHmbO6qVU2AOTVh ZsEmLO5q1Y1AebUhOVvEmDO5q5a1QSYUxOWv0mAOZu7alUTYE5NWP4mAeZs7qpVTeADAAD//66TqMcAAAIISURBVO3TsQ0AAAjDMP4/GnEDmc3exSKzjgCBv8D8JxYECKxyPAGBIqCcomZDQDl gEARUE5RsyGgHD9AoAgop6jZEFCOHyBQBJRT1GwIKMcPECgCyilqNgSU4wcIFAHlFDUbAsrxAwSKgHKKmg0B5fgBAkVAOUXNhoBy/ACBIqCcomZDQDl gEARUE5RsyGgHD9AoAgop6jZEFCOHyBQBJRT1GwIKMcPECgCyilqNgSU4wcIFAHlFDUbAsrxAwSKgHKKmg0B5fgBAkVAOUXNhoBy/ACBIqCcomZDQDl gEARUE5RsyGgHD9AoAgop6jZEFCOHyBQBJRT1GwIKMcPECgCyilqNgSU4wcIFAHlFDUbAsrxAwSKgHKKmg0B5fgBAkVAOUXNhoBy/ACBIqCcomZDQDl gEARUE5RsyGgHD9AoAgop6jZEFCOHyBQBJRT1GwIKMcPECgCyilqNgSU4wcIFAHlFDUbAsrxAwSKgHKKmg0B5fgBAkVAOUXNhoBy/ACBIqCcomZDQDl gEARUE5RsyGgHD9AoAgop6jZEFCOHyBQBJRT1GwIKMcPECgCyilqNgSU4wcIFAHlFDUbAsrxAwSKgHKKmg0B5fgBAkVAOUXNhoBy/ACBIqCcomZDQDl gEARUE5RsyGgHD9AoAgop6jZEFCOHyBQBJRT1GwIKMcPECgCB/GnRcSfso/fAAAAAElFTkSuQmCC

如此困惑。

当我尝试删除base64字符串中的空间并解码。

我无法获得原始图像。

Answer 1

我认为您应该替换选项参数

更改：

NSString *imageString = [imageData base64EncodedStringWithOptions:0];

to：

NSString *imageString = [imageData base64EncodedStringWithOptions:NSDataBase64EncodingEndLineWithLineFeed];

，以防万一您想要：

- (NSString *)imageToNSString:(UIImage *)image
{
    NSData *data = UIImagePNGRepresentation(image);
    return [data base64EncodedStringWithOptions:NSDataBase64EncodingEndLineWithLineFeed];
}
- (UIImage *)stringToUIImage:(NSString *)string
{
    NSData *data = [[NSData alloc]initWithBase64EncodedString:string options:NSDataBase64DecodingIgnoreUnknownCharacters];
    return [UIImage imageWithData:data];
}

请记住，这是iOS 7 API。

Answer 2

替换 to ％2B iOS将所有 替换为"空间，使图像无效

还必须处理它

- (NSString *)base64String:(UIImage*)image {return [[UIImageJPEGRepresentation(image,1) base64EncodedStringWithOptions:NSDataBase64EncodingEndLineWithLineFeed] stringByReplacingOccurrencesOfString:@"+" withString:@"%2B"];}

Answer 3

yap，我发现问题是我不编码URL。

在帖子数据中，我的base64" "字符转换为"字符。

所以我得到了无效的base64字符串。

谢谢洛根。

Answer 4

灵感来自Fadi Abuzant答案，这是Swift 3版本

stringBase64 = stringBase64.replacingOccurrences(of: "+", with: "%2B")