我试图弄清为什么我的代码在取出account_id时不会返回任何数据。我希望它运行并找到符合联接条件和我想要返回的字段的每个帐户。这是在MySQL中,我环顾四周,搜索了谷歌搜索,但没有找到类似的东西,或者只是没有正确地提出。因此,以下是代码,如果有人能帮助我,我将非常感谢它。代码应返回每个account_id 1行我不习惯使用mySQL。版本5.6.34使用TOAD数据点运行SQL脚本。谢谢Dan
SELECT DISTINCT
pd.ACCOUNT_ID
, do.MEMBER_NAME
, do.GENDER
, MaxDate.EarlyDATE AS ACTIVITY_DATE
, MaxDate.LateDATE AS LAST_ACTIVITY_DATE
, pd.NUMBER_WKS
... more fields after this
Joins below
FROM ZZ_Program_Details pd
LEFT JOIN ZZ_Demographics do
ON do.ACCOUNT_ID = pd.ACCOUNT_ID
INNER JOIN
(SELECT DISTINCT cl.ACCOUNT_ID
, min(cl.activity_date) AS EarlyDATE
, cl1.activity_date AS LateDATE
, cl1.scheduling_selection
, cl.ATND_STATUS_THIS_INTERVAL
, cl.WEIGHT_STATUS_FOR_INTERVAL
, TRUNCATE(cl.WEIGHT_WHEN_ENROLLED,2) AS WEIGHT_WHEN_ENROLLED
, TRUNCATE(cl.WEIGHT_AT_INTERVAL_END,2) AS WEIGHT_AT_INTERVAL_END
FROM ZZ_Class_Attendance cl
INNER JOIN ZZ_Class_Attendance cl1
ON cl1.account_id = cl.ACCOUNT_ID
WHERE cl1.ACTIVITY_DATE > cl.ACTIVITY_DATE
/*and cl.account_id = '47F74C65BA8BB02DE053BC010B0AF714'*/
) AS MaxDate
INNER JOIN
(SELECT ESRA.healthfleet_member_id
, ESRA.Sponsor
, ESRA.uhc_region
, ESRA.uhc_major_market
, ESRA.uhc_minor_market AS ESRA_UHC_MINOR_MARKET
, ESRA.policy_number AS ESRA_POLICY_NBR
, ESRA.relationship_code
, sf.Market_Segment
, sf.UHC_Minor_Market AS SF_UHC_MINOR_MARKET
, sf.CLIENT_NAME
, sf.Client_Owner
, sf.Payer_Effective_Date
FROM reporting_adhoc.ZZ_ESRA_People ESRA
LEFT JOIN reporting_adhoc.ZZ_Salesforce sf
ON sf.Policy_Number = ESRA.policy_number
/*WHERE ESRA.healthfleet_member_id='47F74C65BA8BB02DE053BC010B0AF714'*/
GROUP BY ESRA.healthfleet_member_id
, ESRA.Sponsor, ESRA.uhc_region
, ESRA.uhc_major_market
, ESRA.uhc_minor_market
, ESRA.relationship_code
, sf.Market_Segment
, sf.UHC_Minor_Market
, sf.CLIENT_NAME
, sf.Client_Owner, ESRA.policy_number
, sf.Payer_Effective_Date
) ESRA_DATA
ON MaxDate.ACCOUNT_ID = pd.ACCOUNT_ID
AND ESRA_DATA.healthfleet_member_id = pd.ACCOUNT_ID
/*WHERE pd.account_id = '47F74C65BA8BB02DE053BC010B0AF714'* --with this
it works fine */
WHERE pd.account_id > 0 --an attempt with getting all account_ids
GROUP BY
pd.ACCOUNT_ID
, do.MEMBER_NAME
, do.GENDER
, MaxDate.EarlyDATE
, MaxDate.LateDATE
... rest of fields
ORDER BY pd.ACCOUNT_ID
无需访问您的表格和数据,我们可能无法提出一个明确的答案,并且由于您的查询缺少零件,因此它更像是一个猜测游戏。
让我们从这里开始:
SELECT DISTINCT ---------- bad bad
pd.ACCOUNT_ID
, MaxDate.EarlyDATE AS ACTIVITY_DATE
, MaxDate.LateDATE AS LAST_ACTIVITY_DATE
FROM ZZ_Program_Details pd
LEFT JOIN ZZ_Demographics do ON do.ACCOUNT_ID = pd.ACCOUNT_ID
INNER JOIN (
SELECT DISTINCT ---------- bad bad
cl.ACCOUNT_ID
, MIN(cl.activity_date) AS EarlyDATE
, cl1.activity_date AS LateDATE
FROM ZZ_Class_Attendance cl
INNER JOIN ZZ_Class_Attendance cl1 ON cl1.account_id = cl.ACCOUNT_ID
WHERE cl1.ACTIVITY_DATE > cl.ACTIVITY_DATE
-- no GROUP BY, so how do your get MIN() or MAX() ?
) AS MaxDate ON
( WHAT???? )
从上面看到的,将大查询分解成较小的块。此部分查询是否有效?可能不是因为您尝试使用不同的而不是组,并且连接条件也未知。
还请注意,您使用了内部连接。如果该子查询MaxDate
无法返回任何匹配行,则总查询也不会返回行。重新考虑每个内部联接(也许在左联接时尝试它们)。
获得部分查询工作后,添加下一个加入并将相关列添加到顶部选择子句中。在查询的这一部分上工作,直到成功,转到下一个,然后重复直到有工作查询。
请尝试避免在涉及多个连接的复杂查询中使用"选择不同"。这不是一个好习惯。
您可能会发现这些查询将帮助您确定哪些表(或子查询)需要加入:
是否需要:SELECT COUNT(distinct pd.ACCOUNT_ID) acct_c, COUNT(*) row_c
FROM ZZ_Program_Details pd
;
SELECT COUNT(distinct pd.ACCOUNT_ID) acct_c, COUNT(*) row_c
FROM ZZ_Program_Details pd
INNER JOIN ZZ_Demographics do ON pd.ACCOUNT_ID = do.ACCOUNT_ID
;
SELECT COUNT(distinct pd.ACCOUNT_ID) acct_c, COUNT(*) row_c
FROM ZZ_Program_Details pd
LEFT JOIN ZZ_Demographics do ON pd.ACCOUNT_ID = do.ACCOUNT_ID
;
SELECT COUNT(distinct pd.ACCOUNT_ID) acct_c, COUNT(*) row_c
FROM ZZ_Program_Details pd
INNER JOIN ZZ_Class_Attendance cl ON pd.ACCOUNT_ID = cl.ACCOUNT_ID
INNER JOIN ZZ_Class_Attendance cl1 ON cl1.account_id = cl.ACCOUNT_ID
;
SELECT COUNT(distinct pd.ACCOUNT_ID) acct_c, COUNT(*) row_c
FROM ZZ_Program_Details pd
LEFT JOIN ZZ_Class_Attendance cl ON pd.ACCOUNT_ID = cl.ACCOUNT_ID
LEFT JOIN ZZ_Class_Attendance cl1 ON cl1.account_id = cl.ACCOUNT_ID
;
SELECT COUNT(distinct pd.ACCOUNT_ID) acct_c, COUNT(*) row_c
FROM ZZ_Program_Details pd
INNER JOIN reporting_adhoc.ZZ_ESRA_People ESRA ON pd.ACCOUNT_ID = ESRA.healthfleet_member_id
INNER JOIN reporting_adhoc.ZZ_Salesforce sf ON sf.Policy_Number = ESRA.policy_number
;
SELECT COUNT(distinct pd.ACCOUNT_ID) acct_c, COUNT(*) row_c
FROM ZZ_Program_Details pd
LEFT JOIN reporting_adhoc.ZZ_ESRA_People ESRA ON pd.ACCOUNT_ID = ESRA.healthfleet_member_id
LEFT JOIN reporting_adhoc.ZZ_Salesforce sf ON sf.Policy_Number = ESRA.policy_number
;