如何使用JSON.NET将JSON对象(JSON字符串)反序列化为c#对象列表

Question

我试图从URL下载JSON数据，之后我想将该数据绑定到列表。我可以获得JSON数据，但我无法将它们绑定到我创建的类的对象。我该怎么做呢?我创建的类的成员与JSON string的成员相同。

public void getCurrentsJSON(String url) 
{
    using (var w = new WebClient())
    {
        var json_data = string.Empty;
        // attempt to download JSON data as a string
        try
        {
            json_data = w.DownloadString(url);
            Current currents = JsonConvert.DeserializeObject<Current>(json_data);
        }
        catch (Exception) { }
    }    
}

当前类:

 public class Current
    {
        private String currentCode;
        private String currentName;
        private String currentAddress;
        private String currentTel;
        private String fax;
        private String currentProvince;
        private String currentCounty;
        private String taxOffice;
        private String taxNo;
        private String currentType;
        private String postalCode;
        private String countryCode;
        private String additionalCurrentCode;
        public String CurrentCode
        {
            get { return currentCode; }
            set { currentCode = value; }
        }
        public String CurrentName
        {
            get { return currentName; }
            set { currentName = value; }
        }
        public String CurrentAddress
        {
            get { return currentAddress; }
            set { currentAddress = value; }
        }
        public String CurrentTel
        {
            get { return currentTel; }
            set { currentTel = value; }
        }
        public String Fax
        {
            get { return fax; }
            set { fax = value; }
        }
        public String CurrentProvince
        {
            get { return currentProvince; }
            set { currentProvince = value; }
        }
        public String CurrentCounty
        {
            get { return currentCounty; }
            set { currentCounty = value; }
        }
        public String TaxOffice
        {
            get { return taxOffice; }
            set { taxOffice = value; }
        }
        public String TaxNo
        {
            get { return taxNo; }
            set { taxNo = value; }
        }
        public String CurrentType
        {
            get { return currentType; }
            set { currentType = value; }
        }
        public String PostalCode
        {
            get { return postalCode; }
            set { postalCode = value; }
        }
        public String CountryCode
        {
            get { return countryCode; }
            set { countryCode = value; }
        }
        public String AdditionalCurrentCode
        {
            get { return additionalCurrentCode; }
            set { additionalCurrentCode = value; }
        }
    }

JSON数据:

{
    "currents": [
        {
            "currentCode": 1,
            "currentName": "Current1",
            "currentAddress": "CurrentAdress1",
            "currentTel": "CurrentTel1",
            "fax": "Fax1",
            "currentProvince": "CurrentProvince1",
            "currentCounty": "CurrentCounty1",
            "taxOffice": "TaxOffice1",
            "taxNo": "TaxNo1",
            "currentType": "CurrentType1",
            "postalCode": "PostalCode1",
            "countryCode": "CountryCode1",
            "additionalCurrentCode": 1
        }
    ]
}

Answer 1

您需要创建一个模型来描述您获得的JSON。在你的例子中，它可以是这样的:

class GetModel
{
    public IEnumerable<Current> Currents { get; set; }
}

和反序列化:

var model = JsonConvert.DeserializeObject<GetModel>(json);

Answer 2

您可以试试这段代码。

public void getCurrentsJSON(String url) 
{
using (var w = new WebClient())
{
    var json_data = string.Empty;
    // attempt to download JSON data as a string
    try
    {
        json_data = w.DownloadString(url);
        List<Current> currents = JsonConvert.DeserializeObject<List<Current>>(json_data);
    }
    catch (Exception) { }
}    
}

Answer 3

给你，两种方式

dynamic d = JObject.Parse(json_data)

或类////new up your list

List myList = new List<Current>();

/////deserialize

Current currents = JsonConvert.DeserializeObject<RootObject>(json_data);     

public class Current
{
public int currentCode { get; set; }
public string currentName { get; set; }
public string currentAddress { get; set; }
public string currentTel { get; set; }
public string fax { get; set; }
public string currentProvince { get; set; }
public string currentCounty { get; set; }
public string taxOffice { get; set; }
public string taxNo { get; set; }
public string currentType { get; set; }
public string postalCode { get; set; }
public string countryCode { get; set; }
public int additionalCurrentCode { get; set; }
}
 public class RootObject
{
public List<Current> currents { get; set; }
 }

Answer 4

CurrentCode不匹配

你可以通过修饰你的公共属性来帮助反序列化器。

 [JsonProperty("currentCode")]
 public String CurrentCode
    {
        get { return currentCode; }
        set { currentCode = value; }
    }

结合Alex的回答，你应该没问题。