我花了两天时间试图理解为什么我得到了如此不合逻辑的结果。让我举例说明。我基于这个简单的数组创建发票。
Array
(
[0] => Array
(
[userid] => 208
[number_of_services] => 3
[username1] => sara
[income1] => 10
[username2] => mark
[income2] => 18
[username3] => joe
[income3] => 12
)
[1] => Array
(
[userid] => 4
[number_of_services] => 1
[username1] => bruce
[income1] => 5
)
[2] => Array
(
[userid] => 303
[number_of_services] => 1
[username1] => michael
[income1] => 7
)
)
使用此数组，我想为具有以下ID的客户端创建3个发票：208、4和303。我只用一个简单的前臂就可以做到。
foreach($myarray AS $key => $value)
{
// create my invoice
}
现在，您可以看到ID为208的客户端有多个用户名。我将它们存储为[用户名1]、[用户名2]、[用户名3]等等。
[0] => Array
(
[userid] => 208
[number_of_services] => 3
[username1] => sara
[income1] => 10
[username2] => mark
[income2] => 18
[username3] => joe
[income3] => 12
)
我想在发票中将每个用户名显示为新行(项目(，因此我执行以下操作：
foreach($myarray AS $key => $value)
{
for($n=1; $n<=$value["number_of_services"]; $n++)
{
$invoice["itemdescription$n"] = "Username: ".$value["username$n"]."";
$invoice["itemamount$n"] = $value["income$n"];
$invoice["itemtaxed$n"] = 1;
}
}
现在有了这个循环，我应该有：
- 客户4的1张发票，含1件商品(bruce->5欧元(
- 客户303的1张发票，含1件商品(迈克尔->7欧元(
- 客户208的1张发票，包含3项(sara->10，mark->18，joe->12(
但我总是得到：
- 客户4的1张发票，包含3项商品(bruce->5欧元，mark->18，joe->12(
- 客户303的1张发票，包含3项商品(迈克尔->7欧元，马克->18，乔->12(
- 客户208的1张发票，包含3项(sara->10，mark->18，joe->12(
我不明白为什么脚本不断将客户端208的[username2]、[income2]和[username3]、[incone3]"合并"到客户端4和303中！我在每一步都调试了脚本，问题似乎出现在for((循环中。
知道吗？
foreach($myarray AS $key => $value)
{
for($n=1; $n<=$value["number_of_services"]; $n++)
{
$invoice[] = array(
"itemdescription" => "Username: " . $value . "username" . $n,
"itemamount" . $n = $value . "income" . $n,
"itemtaxed" . $n = 1
);
}
}
试试这个。